mersenneforum.org Factoring Double mersennes
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 2005-10-02, 06:19 #1 Citrix     Jun 2003 64616 Posts Factoring Double mersennes MMn= 2^(Mn)-1 Based on http://www.primepuzzles.net/conjectures/conj_015.htm if MMn is prime then 2^(Mn)+1/3 will also be. So can we try factoring 2^(Mn)+1/3? Has any work been done on this? Citrix Last fiddled with by Citrix on 2005-10-02 at 06:20
2005-10-02, 18:07   #2
jinydu

Dec 2003
Hopefully Near M48

2×3×293 Posts

Quote:
 Originally Posted by Citrix MMn= 2^(Mn)-1 Based on http://www.primepuzzles.net/conjectures/conj_015.htm if MMn is prime then 2^(Mn)+1/3 will also be. So can we try factoring 2^(Mn)+1/3? Has any work been done on this? Citrix
Well, it's a conjecture. It hasn't been proven yet...

 2005-10-04, 08:08 #3 geoff     Mar 2003 New Zealand 13×89 Posts My logic might be letting me down here, but since p=M(n) automatically satisfies the first condition of the NMC when M(n) is a Mersenne prime, finding a factor of (2^M(n)+1)/3, as Citrix suggests, would prove that either the double Mersenne MM(n) is composite or the NMC is false. If we didn't already know that MM(n) was composite wouldn't that be progress?

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