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#1 |
Jan 2010
germany
328 Posts |
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Hello,
My conjecture is : Let a is an element from (1) --> (2) This means, that if (1) is true, than is (2) also true. It is easy to show that ? My idea to do this with When and therefore: - But the only solution to this is 1: --> -> So I have searched with google many sites, but could not find the answer to this "problem". I hope that anybody can help me with the conjecture. kind regards, sascha |
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#2 |
"Gary"
May 2007
Overland Park, KS
5·23·103 Posts |
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This should be posted in the GIMPS forum.
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#3 |
Jan 2010
germany
1A16 Posts |
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ok. thanks.
I will post this in the gimps->math Forum |
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