20090728, 17:18  #12 
Dec 2008
you know...around...
2×5^{2}×17 Posts 
Meh.
You don't think the number will change its mind someday? Oh well... here's the minimal set of square numbers up to 8.5*10^26: 1 4 9 25 36 576 676 7056 80656 665856 2027776 2802276 22282727076 77770707876 78807087076 7888885568656 8782782707776 72822772707876 555006880085056 782280288087076 827702888070276 888288787822276 2282820800707876 7880082008070276 80077778877070276 88778000807227876 782828878078078276 872727072820287876 2707700770820007076 7078287780880770276 7808287827720727876 8008002202002207876 27282772777702807876 70880800720008787876 72887222220777087876 80028077888770207876 80880700827207270276 87078270070088278276 88002002000028027076 2882278278888228807876 8770777780888228887076 77700027222828822007876 702087807788807888287876 788708087882007280808827876 including the number 0² gives 0 1 4 9 25 36 576 676 665856 7888885568656 888288787822276 (< will this be the last number in the list??) 
20090808, 15:30  #13 
Dec 2008
you know...around...
2·5^{2}·17 Posts 
Digital sum of the last m digits of x^n < digital sum of x (for x < 10^m):
For n even, this is always 10^m1, but for odd n there are some irregularities: n=3, m=1: {8} n=3, m=2: {87} n=3, m=3: {887} n=3, m=4: {8887} n=3, m=5: {99868} n=3, m=6: {978887} n=3, m=7: {7978887} n=5, m=1: {1...9} n=5, m=2: {81, 87} n=5, m=3: {887, 994} n=5, m=4: {9983, 9994} n=5, m=5: {98994, 99594} n=5, m=6: {989594} n=5, m=7: {9899982} n=7, m=1: {8} n=7, m=2: {78, 97} n=7, m=3: {978} n=7, m=4: {9978} n=7, m=5: {69978} n=7, m=6: {869978} n=7, m=7: {9799978} 
20090905, 11:57  #14 
Dec 2008
you know...around...
2×5^{2}×17 Posts 
I wonder if anyone has thought of this before:
With this formula, you get the time on your "lifeclock": in hours For example, if you're 36 then you're at 2 P.M. in the day of your life. A similar formula projecting a lifespan into one year will return August, 1st for this age: in months, starting at Jan. 1st or, more precisely, in days, depending on whether you want to take an average Julian or Gregorian year into account. Note that you have to count 6 hours, or 5 h 49 m 12 s respectively, of Feb. 29th, if you want to be that precise. Last fiddled with by mart_r on 20090905 at 11:57 
20090905, 12:09  #15  
Undefined
"The unspeakable one"
Jun 2006
My evil lair
2×13×257 Posts 
Quote:


20090905, 14:34  #16  
Dec 2008
you know...around...
352_{16} Posts 
Quote:
But I pictured the end of the range at the beginning of a life, i.e. at the age of 144. Last fiddled with by mart_r on 20090905 at 14:36 

20090905, 21:06  #17  
"Richard B. Woods"
Aug 2002
Wisconsin USA
1111000001100_{2} Posts 
Quote:
Quote:
   Oh, I see  you're starting at 2 AM    ?? Last fiddled with by cheesehead on 20090905 at 21:14 

20090905, 21:35  #18 
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
1000010110111_{2} Posts 
Actually, people are 0 years old (but almost always measured in days/weeks/months so as to have a >0 measure ) before they're 1 year old.
So it starts at 0 (12 midnight) o'clock And so someone living to 144 would live from midnight to 2 am the next day. (similarly, a 121 year old would be midnight to midnight) 
20090906, 11:07  #19  
Dec 2008
you know...around...
352_{16} Posts 
Quote:
If 121 years is midnight > midnight, then it would have to be ? It's a symbolic measure, and it just fits better with the "+1" term in it. It's rather useless from a completely mathematical point of view. And yes, if you're 144 that would be 2 A.M. again. If I would go further, I'd say every soul reincarnates after 144 years, and so noone can surpass this age. Hey, how 'bout a "square root of age plus one" cult? 

20090906, 11:23  #20 
Undefined
"The unspeakable one"
Jun 2006
My evil lair
6682_{10} Posts 
Maybe it starts at 9 months?
Last fiddled with by retina on 20090906 at 11:25 Reason: w00t, my first ever tex thingy. And it worked 8) 
20090906, 13:26  #21 
May 2004
New York City
5×7×11^{2} Posts 
We always did know pregnancy was COMPLEX.

20090906, 20:34  #22 
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
1000010110111_{2} Posts 

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