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#1 |
Mar 2018
72×11 Posts |
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Pg(215), pg(69660),pg(92020) pg(541456) are prp with 215, 69660, 92020 and 541456 multiple of 43.
215, 69660, 92020, 541456 are plus/minus 344 mod 559 lcm(344,559)=4472 4472=8*331+456*4 Pg(331259) is prp 331259=331+(8*331+456*4)*s with some integer s And 331259 leaves the same remainder 331 mod 344 and mod 559 215, 69660, 92020, 541456 are 10^m mod 41 multiple of 43 and congruent to (41*(10^2+1)+331)/13 mod (41*(10^2+1)+331)/8 Last fiddled with by enzocreti on 2020-06-20 at 11:32 |
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