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#1 |
Nov 2008
503 Posts |
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In the recently cleared exponents list is this little entry
Jacques MOLNE mon_4 4096 F-ECM 2015-07-03 00:08 5.5 1.0369 45477879701734570611058964078361695337745924097 Thought all exponents had to be prime which clearly an even number isn't (apart from 2 to head off RDS) |
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#2 |
Jun 2003
2×2,683 Posts |
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F-ECM stands for Fermat-ECM. This is a result of ECM run on 2^4096+1. Incidentally, the factor found is a composite one consisting of some of the previously-known factors for that number. As for "should it be there in the cleared exponents list", I'll let the project admins make that decision.
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#3 | |
1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
3·11·157 Posts |
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I suspect NONE of these 113 are NEW. Code:
Top ECM on Fermat numbers producers for the last year. Total | Rank Change | Overtake date based on Rank Member Name GHz-Days Attempts Successes |90day 30day 7 day 1 day | 90 days 30 days 7 days ------ -------------------- ------------ -------- --------- |----- ----- ----- ----- | ------- ------- ------- 1 David Bessell 43850.855 6261 0 | | >999dy 2 Jacques MOLNE 33930.562 2831 113 | | Code:
PrimeNet Most Recent Cleared Not-Prime This report updates every hour on the hour. This report produced 2015-07-03 15:00 UTC Member Name Computer Name Exponent Type UTC Time Received Days GHz-days Result Jacques MOLNE mon_4 4096 F-ECM 2015-07-03 10:05 5.9 1.0369 45477879701734570611058964078361695337745924097 Jacques MOLNE mon_4 4096 F-ECM 2015-07-03 00:08 5.5 1.0369 45477879701734570611058964078361695337745924097 Jacques MOLNE mon_4 4096 F-ECM 2015-07-02 17:33 5.2 1.0369 45477879701734570611058964078361695337745924097 Jacques MOLNE mon_4 4096 F-ECM 2015-07-02 06:30 4.7 1.0369 45477879701734570611058964078361695337745924097 ECM2=k,b,n,c,B1,B2,curves_to_run[,"comma-separated-list-of-known-factors"] Last fiddled with by petrw1 on 2015-07-03 at 15:40 Reason: ECM2=... |
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#4 | |
∂2ω=0
Sep 2002
República de California
2DD016 Posts |
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#5 | |
Einyen
Dec 2003
Denmark
63618 Posts |
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Edit: Except 0 and 1 I guess. Last fiddled with by ATH on 2015-07-04 at 08:43 |
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#6 | |
Jun 2003
10100111101102 Posts |
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Consider the polynomial b^4 + 8*b^2 + 15 = (b^2+3)*(b^2+5) represented by the digits 1080F. This can never yield a prime (not even in negative bases). |
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#7 |
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
3×29×113 Posts |
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