mersenneforum.org Is There A Breakthrough For The Mersenne Primes?
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 2015-01-08, 17:56 #1 Owl   Aug 2014 3 Posts Is There A Breakthrough For The Mersenne Primes? As the consequence of the Riemann Hypothesis see the complete generalization at the Theorem 11 (30), (31), i would submit to you the following. The questions are how far the relation holds true and is it very helpful for the Mersenne Primes Project. Thank you. ps: The mentioned article will be updated soon. I apologize for any confusion. Last fiddled with by Owl on 2015-01-08 at 17:56
 2015-01-08, 18:25 #2 Batalov     "Serge" Mar 2008 Phi(4,2^7658614+1)/2 23×1,201 Posts Blech... inb4miscmath
 2015-01-08, 18:36 #3 Batalov     "Serge" Mar 2008 Phi(4,2^7658614+1)/2 100101100010002 Posts In case you were wondering, here's a professional opinion that sums it all up nicely http://randomprocessed.blogspot.com/...ndividual.html Dozens of boards around the net are swamped with that nonsense. We have been honored to be added to the list.
 2015-01-09, 00:18 #4 Uncwilly 6809 > 6502     """"""""""""""""""" Aug 2003 101×103 Posts 235608 Posts
 2015-01-09, 05:54 #5 LaurV Romulan Interpreter     "name field" Jun 2011 Thailand 2·4,903 Posts grrr.... +1 for ban (edit: wait to see if he insists with is, maybe it is just a guy asking?) Last fiddled with by LaurV on 2015-01-09 at 05:54
2015-01-09, 17:03   #6
R.D. Silverman

Nov 2003

1D2416 Posts

Quote:
 Originally Posted by LaurV grrr.... +1 for ban (edit: wait to see if he insists with is, maybe it is just a guy asking?)
BTW,

This nonsense is not new. This crank posted the same crap a number of years ago.

 2015-01-09, 17:11 #7 petrw1 1976 Toyota Corona years forever!     "Wayne" Nov 2006 Saskatchewan, Canada 5·967 Posts With only High School math Seems to me that function holds true for any p; Mersenne or not; Prime or not; Even or odd.
2015-01-09, 17:52   #8
R.D. Silverman

Nov 2003

164448 Posts

Quote:
 Originally Posted by petrw1 Seems to me that function holds true for any p; Mersenne or not; Prime or not; Even or odd.
False.

 2015-01-09, 20:24 #9 danaj   "Dana Jacobsen" Feb 2011 Bangkok, TH 32·101 Posts OK, so for what $p$ does $\frac{2^{(p+4)} + 2^3}{2^4} - \frac{3}{2} \ \ne\ 2^p-1$ ?
2015-01-09, 21:02   #10
Mini-Geek
Account Deleted

"Tim Sorbera"
Aug 2006
San Antonio, TX USA

3×1,423 Posts

Quote:
 Originally Posted by danaj OK, so for what $p$ does $\frac{2^{(p+4)} + 2^3}{2^4} - \frac{3}{2} \ \ne\ 2^p-1$ ?
That part is correct, of course. But the equation also says that $2^p-1 = \zeta(p+4)$, which is obviously untrue.

Last fiddled with by Mini-Geek on 2015-01-09 at 21:05

2015-01-09, 21:25   #11
danaj

"Dana Jacobsen"
Feb 2011
Bangkok, TH

32·101 Posts

Quote:
 Originally Posted by Mini-Geek That part is correct, of course. But the equation also says that $2^p-1 = \zeta(p+4)$, which is obviously untrue.
Of course that isn't right. I assumed he was making up another symbol like many of his texts, not that he meant the actual Riemann Zeta function. We're left wondering if it's amazingly wrong or amazingly trivial and non-useful.

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