20210602, 00:06  #1 
"Mike"
Aug 2002
2056_{16} Posts 
June 2021

20210602, 00:50  #2 
Jan 2017
5·23 Posts 
The second required property is completely meaningless as currently phrased. I assume it should say the numbers have to be at least 2.
Last fiddled with by uau on 20210602 at 00:51 
20210602, 07:56  #3 
Romulan Interpreter
Jun 2011
Thailand
9753_{10} Posts 
What do you mean? That is the most important filtering criteria. Under a million, there are only about 40 numbers which suffice, and of them, less that a handful are prime.

20210602, 08:12  #4 
Oct 2017
118_{10} Posts 

20210602, 08:20  #5  
Undefined
"The unspeakable one"
Jun 2006
My evil lair
2^{2}·5·313 Posts 
Quote:
Quote:
The page has been edited to show "... > 1". Before it said "... ≥ 1" 

20210602, 08:41  #6 
Romulan Interpreter
Jun 2011
Thailand
3·3,251 Posts 

20210622, 17:15  #7 
Jun 2012
2·3·17·31 Posts 
Fun problem. Believe I got a correct answer.
Anybody go for the bonus *? 
20210622, 20:10  #8 
Jan 2020
2^{2}×3^{2} Posts 
My bottleneck is primality proving.
I used YAFU implementation of APRCL for solutions with less than 2k digits. 
20210623, 01:14  #9 
Feb 2017
Nowhere
1001011001100_{2} Posts 

20210623, 04:31  #10 
Jan 2020
2^{3} Posts 
Solved it today, largest solution I found so far is greater than 10^545
Last fiddled with by Yusuf on 20210623 at 05:18 
20210624, 22:02  #11  
"Kebbaj Reda"
May 2018
Casablanca, Morocco
3·31 Posts 
Quote:
Go to the maximum yusuf. we compare our max after the solution. if you want? Last fiddled with by Kebbaj on 20210624 at 22:52 

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