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Old 2012-11-21, 23:29   #1
c10ck3r
 
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Default On Fermat's Last Number

Quote:
Originally Posted by rajula View Post
Batalov: with this speed you will factorize all the Fermat numbers before Christmas!
Yes, I'm sure Sergei will factorize all Fermat numbers, regardless of how long it takes to prove primality for the infinite number of infinitely large numbers...
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Old 2012-11-22, 08:12   #2
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Quote:
Originally Posted by c10ck3r View Post
Yes, I'm sure Sergei will factorize all Fermat numbers, regardless of how long it takes to prove primality for the infinite number of infinitely large numbers...
Luckily there are zero infinitely large numbers.
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Old 2012-11-22, 14:45   #3
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Quote:
Originally Posted by rajula View Post
Luckily there are zero infinitely large numbers.
Ah. So, how many base 10 digits in the last Fermat number?
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Old 2012-11-22, 15:01   #4
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Quote:
Originally Posted by c10ck3r View Post
Ah. So, how many base 10 digits in the last Fermat number?
Any last Fermat number has 42 digits in base 10.
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Old 2012-11-22, 15:26   #5
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Quote:
Originally Posted by rajula View Post
Any last Fermat number has 42 digits in base 10.
Say what now? F24 is a composite of over 5,000,000 digits base 10.
5000000 != 42
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Old 2012-11-22, 15:47   #6
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Not a counter-example, c10ck3r, as F24 is not the or a last Fermat number.
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Old 2012-11-23, 22:56   #7
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Yes, but they continue to grow exponentially, no?
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Old 2012-11-23, 23:22   #8
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Yes, doubly-exponentially in the index, in fact!
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Old 2012-11-23, 23:44   #9
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so, 5050446*2^x> 42, when x>1
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Old 2012-11-26, 12:07   #10
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This is correct for every integer x > 1, but not for the last one.
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Old 2012-11-28, 21:53   #11
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I think "42" is the answer to the question of the meaning of life and everything in The Hitchhiker's Guide to the Galaxy, maybe that's what rajula is referring to?
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