20080930, 21:10  #1 
1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
3·11·157 Posts 
3+3+2+2+1=11
".THREE" ".THREE" "...TWO" "...TWO" "...ONE" "======" "ELEVEN" Wasn't sure how to get the spacing right without periods, anyway on to the puzzle: Substitute the appropriate digit for each corresponding letter to make a valid mathematical equality. 
20080930, 21:18  #2 
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
7·13·47 Posts 
Code:
THREE THREE TWO TWO ONE ====== ELEVEN Not so sure about the actual problem though...I was thinking E=1 since T+T = Ex, but since there's not just two numbers being added, I think it's possible for E to be something else 
20080930, 21:30  #3 
6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
5^{2}×421 Posts 
Which base?
Last fiddled with by Uncwilly on 20080930 at 21:31 
20080930, 21:56  #4 
1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
143D_{16} Posts 
I have an answer for base 10 but if you want to try another base??
Actually since there are 9 different letters it can only be base 9 or 10 (and above?) Clarification: The same digit CANNOT be assigned to two different letters Last fiddled with by petrw1 on 20080930 at 21:57 
20081001, 15:06  #5 
Jun 2003
12364_{8} Posts 
84611
84611 ..803 ..803 ..391  171219 
20081001, 20:19  #6 
1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
3·11·157 Posts 
axn1: Did you use brute force or were you able to solve much of it with logic?
It took me a couple hours (after restarting a couple times after dumb assumptions) on pencil and paper. 
20081001, 20:54  #7 
Jun 2003
14F4_{16} Posts 
