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 2008-09-30, 21:10 #1 petrw1 1976 Toyota Corona years forever!     "Wayne" Nov 2006 Saskatchewan, Canada 3·11·157 Posts 3+3+2+2+1=11 ".THREE" ".THREE" "...TWO" "...TWO" "...ONE" "======" "ELEVEN" Wasn't sure how to get the spacing right without periods, anyway on to the puzzle: Substitute the appropriate digit for each corresponding letter to make a valid mathematical equality.
 2008-09-30, 21:18 #2 Mini-Geek Account Deleted     "Tim Sorbera" Aug 2006 San Antonio, TX USA 7·13·47 Posts Code:  THREE THREE TWO TWO ONE ====== ELEVEN Code tags. [ code ] [ /code ] (without the spaces) Not so sure about the actual problem though...I was thinking E=1 since T+T = Ex, but since there's not just two numbers being added, I think it's possible for E to be something else
2008-09-30, 21:30   #3
Uncwilly
6809 > 6502

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Aug 2003
101×103 Posts

52×421 Posts

Quote:
 Originally Posted by petrw1 Substitute the appropriate digit for each corresponding letter to make a valid mathematical equality.
Which base?

Last fiddled with by Uncwilly on 2008-09-30 at 21:31

2008-09-30, 21:56   #4
petrw1
1976 Toyota Corona years forever!

"Wayne"
Nov 2006

143D16 Posts

Quote:
 Originally Posted by Uncwilly Which base?
I have an answer for base 10 but if you want to try another base??

Actually since there are 9 different letters it can only be base 9 or 10 (and above?)

Clarification: The same digit CANNOT be assigned to two different letters

Last fiddled with by petrw1 on 2008-09-30 at 21:57

 2008-10-01, 15:06 #5 axn     Jun 2003 123648 Posts 84611 84611 ..803 ..803 ..391 ------ 171219
 2008-10-01, 20:19 #6 petrw1 1976 Toyota Corona years forever!     "Wayne" Nov 2006 Saskatchewan, Canada 3·11·157 Posts axn1: Did you use brute force or were you able to solve much of it with logic? It took me a couple hours (after restarting a couple times after dumb assumptions) on pencil and paper.
2008-10-01, 20:54   #7
axn

Jun 2003

14F416 Posts

Quote:
 Originally Posted by petrw1 brute force

apart from the entirely trivial "e = 1" bit, that is.

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