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#1 |
1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
3·11·157 Posts |
![]() ".THREE" ".THREE" "...TWO" "...TWO" "...ONE" "======" "ELEVEN" Wasn't sure how to get the spacing right without periods, anyway on to the puzzle: Substitute the appropriate digit for each corresponding letter to make a valid mathematical equality. |
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#2 |
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
7·13·47 Posts |
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THREE THREE TWO TWO ONE ====== ELEVEN Not so sure about the actual problem though...I was thinking E=1 since T+T = Ex, but since there's not just two numbers being added, I think it's possible for E to be something else |
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#3 |
6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
52×421 Posts |
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Which base?
Last fiddled with by Uncwilly on 2008-09-30 at 21:31 |
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#4 |
1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
143D16 Posts |
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I have an answer for base 10 but if you want to try another base??
Actually since there are 9 different letters it can only be base 9 or 10 (and above?) Clarification: The same digit CANNOT be assigned to two different letters Last fiddled with by petrw1 on 2008-09-30 at 21:57 |
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#5 |
Jun 2003
123648 Posts |
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84611
84611 ..803 ..803 ..391 ------ 171219 |
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#6 |
1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
3·11·157 Posts |
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axn1: Did you use brute force or were you able to solve much of it with logic?
It took me a couple hours (after restarting a couple times after dumb assumptions) on pencil and paper. |
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#7 |
Jun 2003
14F416 Posts |
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