20130201, 18:13  #1 
Aug 2010
Kansas
547 Posts 
Sieving k*2^n1 With Fixed n
Okay, so I'm afraid I'm reviving an old thread, but I don't think my question really has enough substance to merit a new thread. My question is:
How would one go about creating a test file for numbers of the form k*2^n1 or k*2^n+1 for a set "n" value other than using Newpgen? Or, I guess the question I should be asking is: What is the most efficient method for doing so? Thanks in advance! 
20130201, 20:14  #2  
"Mark"
Apr 2003
Between here and the
3^{2}·701 Posts 
Quote:


20130201, 22:48  #3 
Aug 2010
Kansas
1043_{8} Posts 

20130202, 02:58  #4 
"Mark"
Apr 2003
Between here and the
3^{2}×701 Posts 

20130202, 03:24  #5 
Nov 2003
2·1,811 Posts 
Newpgen works great for fixed n, have you tried it?

20130202, 04:12  #6 
Aug 2010
Kansas
547 Posts 

20130202, 14:23  #7 
"Carlos Pinho"
Oct 2011
Milton Keynes, UK
11477_{8} Posts 
k*2^n1, k<300
If you want to help on Riesel primes search for k*2^n1, k<300, you need to check webpage http://www.15k.org/riesellist.html because this one has the latest updates.
Carlos 
20130202, 15:48  #8 
Apr 2010
Over the rainbow
2^{2}×641 Posts 
ppsieve might work

20130202, 16:25  #9  
Aug 2010
Kansas
547 Posts 
Quote:


20130202, 16:44  #10 
"Mark"
Apr 2003
Between here and the
3^{2}·701 Posts 
Can I ask why you would want such a sieve? Note that a sieve like that would be very inefficient compared to existing sieves. It wouldn't scale very well as the range of k increases.

20130202, 16:55  #11  
Aug 2010
Kansas
547 Posts 
Quote:
Think lines 9951230, except make them top500. Zat's the goal... 

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