20200210, 09:05  #1 
May 2017
ITALY
19^{2} Posts 
RSA factorization... NOT
if N = p * q such that (p+q4) mod 8 = 0
then (M^2+2*(M3)*M1)/83*y*(y1)/2=(3*N1)/8 and (3*N1)/8=3*x*(x+1)/23*y*(y1)/2+(3*x+1)*(3*x+2)/2 where M=4*x+3 and qp =4*y2 Example N=91 (M^2+2*(M3)*M1)/83*y*(y1)/2=34 (M^2+2*(M3)*M1)/8y*(y1)/2=34+y*(y1) therefore solve integer (M^2+2*(M3)*M1)/8y*(y1)/2=H which has 16 solutions to establish the infinite solutions so let's say we try them all and get here H=4*(6*c^2+3*c8*d3*d) , M=8*c+3 ,y=8*d+2 H=34+(8*d+2)*(8*d+21)=4*(6*c^2+3*c8*d3*d) solve 34=3*x*(x+1)/23*y*(y1)/2+(3*x+1)*(3*x+2)/2 , y=8*d+2 , 8*c+3=4*x+3 , 34+(8*d+2)*(8*d+21)=4*(6*c^2+3*c8*d3*d) and obtain c=1 ,d=0 , x=2, y=2 
20200210, 10:04  #2 
Romulan Interpreter
Jun 2011
Thailand
2^{6}×131 Posts 

20200210, 10:10  #3  
May 2017
ITALY
101101001_{2} Posts 
Quote:
M is definitely in the form 8 * c + 3 or 8 * c + 7 then giving y values 8 * d or 8 * d + 1 or .... or 8 * d + 7 there are 16 solutions 

20200210, 10:14  #4 
May 2017
ITALY
551_{8} Posts 

20200210, 10:31  #5 
Undefined
"The unspeakable one"
Jun 2006
My evil lair
12270_{8} Posts 

20200211, 08:26  #6 
May 2017
ITALY
101101001_{2} Posts 
N=91
34=3*x*(x+1)/23*y*(y1)/2+(3*x+1)*(3*x+2)/2 , (3*(H1)1)/8+3*(2*(3*(H1)1)/82)/3*(2*(3*(H1)1)/82+3)/3/23*y*(y1)/2=34 , 2*[2*[3*x+1(xy+1)]+1](4*y2)=H then q=2*[3*x+1(xy+1)]+1 p=2*[3*x+1(xy+1)]+1(4*y2) Last fiddled with by Alberico Lepore on 20200211 at 08:36 
20200211, 16:29  #7 
May 2017
ITALY
19^{2} Posts 
The RSA secret is revealed by this image

20200211, 18:08  #8 
"Ben"
Feb 2007
5×647 Posts 
Outstanding. Now just make the x and y axes of that chart 150 orders of magnitude larger.

20200213, 06:43  #9 
Romulan Interpreter
Jun 2011
Thailand
2^{6}×131 Posts 
RSA secret? ... hm.. not interested.
Please post an image with the NSA secret. Last fiddled with by LaurV on 20200213 at 06:43 
20200214, 19:02  #10 
May 2017
ITALY
19^{2} Posts 
if N = p * q such that (p+q4) mod 8 = 0
if this system admits solutions [((3*N1)/81)/3+y*(y1)/21[4*x+4]*x/2]+4*x*(4*x+1)/2c=(3*N1)/8+3*y*(y1)/23 , [((3*N1)/81)/3+y*(y1)/214*x[4*(x1)+4]*(x1)/2]+4*(x1)*(4*(x1)+1)/2[c+2sqrt(8*c+8)]=(3*N1)/8+3*y*(y1)/2312*x , (3*N1)/8=3*x*(x+1)/23*y*(y1)/2+(3*x+1)*(3*x+2)/2 then q=2*[3*x+1(xy+1)]+1 please someone help me solve the system 
20200214, 20:12  #11 
"Curtis"
Feb 2005
Riverside, CA
111110011101_{2} Posts 
Why can't you solve your own systems? If you can't, you should conclude that your methods are far too complicated to be useful to anyone (even yourself, since you can't solve them).

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