20201211, 06:35  #1 
Dec 2017
2^{4}×3×5 Posts 
Prediction Next Exponent which produces a Mersenne Prime #52
I firmly believe the next exponent that produces a Mersenne Prime if you do this to it:
It will equal Zero if you mod 6 to it after a minus 1! exponent1Mod6 will equal Zero exponent1 % 6 = 0 I base this on the many exponents that follow a certain pattern which build perfect numbers will always and must have an occasional number when minus 1 mod 6 to the exponent it will be ZERO. I call this the ONeil perfect number Conjecture! 
20201211, 06:44  #2 
Undefined
"The unspeakable one"
Jun 2006
My evil lair
1011111000100_{2} Posts 

20201211, 06:46  #3 
Dec 2017
2^{4}×3×5 Posts 
However we are due for a zero its lined up for one! The pattern should be 100% for 52 right or wrong.
Last fiddled with by ONeil on 20201211 at 06:48 
20201211, 06:52  #4 
Undefined
"The unspeakable one"
Jun 2006
My evil lair
2^{2}×3^{2}×13^{2} Posts 

20201211, 07:08  #5  
Dec 2017
360_{8} Posts 
Quote:
Here is the basic math 24 of the numbers from 51 of them when using minus 1 mod 6 to equal ZERO: 5124=27 So if 27 of the numbers do not compute to ZERO than I say that the ONeil conjecture should hold for the next exponent equal a ZERO when minus 1 mod 6. Last fiddled with by ONeil on 20201211 at 07:53 

20201211, 07:18  #6  
Undefined
"The unspeakable one"
Jun 2006
My evil lair
2^{2}·3^{2}·13^{2} Posts 
Quote:
That is numerology. Also, read up on the gambler's fallacy. Last fiddled with by retina on 20201211 at 07:19 

20201211, 07:43  #7 
Dec 2017
2^{4}·3·5 Posts 
The exponents seek to be equal with just under half showing a ZERO when using the minus 1 mod 6 formula. It is because of the number line and that is the reason. Since Perfect numbers must equal the sum of their divisors and the first one is 6 than you should always see about half of the exponents follow the ONeil conjecture where minus 1 mod 6! the numbers shall show up to balance or be over so that ZERO will seek to be half of the exponents to infinity. Yes the number shall get unbalanced like 24 and 27 but we are due for another ZERO now.
My Premise is that ZERO will follow this rule and should seek to even out as many as we find: 
20201211, 07:59  #8  
Undefined
"The unspeakable one"
Jun 2006
My evil lair
17C4_{16} Posts 
Quote:


20201211, 15:09  #9 
Mar 2019
144_{10} Posts 
You realize this is just you saying that you *want* there to be this perfect symmetry, right? You haven't given any mathematical reason for it to be the case. It could just as well be that 1/3 are 5 mod 6, or 2/3 are, or 1/e, or any other constant.

20201213, 17:14  #10 
Feb 2017
Nowhere
43×101 Posts 

20201214, 07:57  #11  
Aug 2006
2×29×103 Posts 
Quote:
But if you say you're 100% sure, I take that to mean you're closer to 100% sure than to 99% sure, so at least 99.5% sure. In that case, if I wagered $20 that the next exponent would be 5 mod 6, you'd be comfortable wagering $4000 against that. Is this really how you feel? 

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