20160608, 01:20  #1 
Sep 2002
Database er0rr
5×719 Posts 
Alternative to LL
Code:
f(p)=mp=2^p1;a=Mod(2,mp);for(b=1,p1,a=(a/2+1/a));a==2 
20160608, 02:03  #2 
Romulan Interpreter
Jun 2011
Thailand
22073_{8} Posts 

20171113, 23:49  #3  
Sep 2002
Database er0rr
5·719 Posts 
Quote:
Code:
f(p)=mp=2^p1;a=Mod(2,mp);for(b=1,p1,a=(a/2+3/a));a==0 Last fiddled with by paulunderwood on 20171113 at 23:56 

20171113, 23:56  #4 
"Forget I exist"
Jul 2009
Dumbassville
20C0_{16} Posts 
comes down to where the squares are on the arithmetic progression y(mp)6. parity of x is the parity of y.
Last fiddled with by science_man_88 on 20171113 at 23:57 
20171211, 00:56  #5 
Sep 2002
Database er0rr
5·719 Posts 
Here is another test for Mersennes:
Code:
f(p)=local(mp=2^p1,a=Mod(2,mp),b);for(b=3,p,a=a^2*21);a==0 
20171211, 01:05  #6  
"Forget I exist"
Jul 2009
Dumbassville
2^{6}×131 Posts 
Quote:
Last fiddled with by science_man_88 on 20171211 at 01:08 

20171211, 02:54  #7 
"Sam"
Nov 2016
2·163 Posts 
I don't know if this is useful but https://oeis.org/A002812 happens to be the subset of the sequence https://oeis.org/A110293. Like the Mersenne sequence 2^n1, this is also a divisibility sequence.
a(n) = 2*a(n1)^2  1, starting a(0)=n b(n) = b(n1)^22, starting b(0)=n are generalizations of https://oeis.org/A110293 I don't know the sequences which a(n) or b(n) are subsets of. That is, there exists sequences A(n) and B(n) such that A(2^n) = a(n) B(2^n) = b(n) The sequences a(n) and b(n) For further discussion let ll(2^n) be the sequence in https://oeis.org/A002812 and ll(n) be the sequence in https://oeis.org/A110293 Another question that comes up is how are ll(n) and 2^n1 related to eachother other than the fact that if 2^n1 is prime, then 2^n1 divides ll(2^(n2)). 
20180502, 15:37  #8  
Sep 2002
Database er0rr
5×719 Posts 
Quote:
1^2+6 == 0 mod 2^31 5^2+6 == 0 mod 2^51 11^2+6 == 0 mod 2^71 1405^2+6 == 0 mod 2^131 Last fiddled with by paulunderwood on 20180502 at 15:40 

20180502, 17:32  #9 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}·131 Posts 
12²+6== 0 mod 2^41
Last fiddled with by science_man_88 on 20180502 at 17:32 
20180502, 17:57  #10  
Feb 2017
Nowhere
2^{3}·3·181 Posts 
Quote:
;) Last fiddled with by Dr Sardonicus on 20180502 at 18:05 

20180502, 18:40  #11 
Dec 2017
11110000_{2} Posts 
Paul can you elaborate on this concept of rapid verification of Mprime?.

Thread Tools  
Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Fulsorials  a1call  Miscellaneous Math  46  20200803 00:31 
Java applet alternative  a1call  Programming  19  20191108 22:31 
alternative ( points of view )  cmd  cmd  51  20190928 14:56 
CEMPLLA: An alternative to GIMPS ?  CEMPLLA Author  Data  233  20190628 17:18 
free alternative to EasyFit?  ixfd64  Software  1  20080426 21:28 