20220410, 16:22  #1 
Feb 2019
2·47 Posts 
Beal's conjecture ..........not
PROOF OF BEAL'S CONJECTURE

20220410, 16:56  #2 
"Καλός"
May 2018
5×73 Posts 
It is stated in the article that "... every term in each of the 2 brackets must be integers and not irrational numbers."
However, please note that the product of two irrational numbers can be an integer. 
20220410, 18:01  #3 
Feb 2019
2·47 Posts 
The fact that the product of 2 irrational numbers can produce a rational number is not too relevant in my argument because I am talking about numerical values here. Take for instance the numerical value of square root of 2. This numerical value can be written to any desired number of decimal places which will not be the exact value. Hence, the numerical value of square root of 2 is only an approximation.

20220410, 22:37  #4 
"Robert Gerbicz"
Oct 2005
Hungary
62A_{16} Posts 
Recommending 6 (six) more problems what you could easily attack: https://en.wikipedia.org/wiki/Millennium_Prize_Problems
all of them worth 1 million bucks (USD). 
20220410, 23:00  #5 
Feb 2019
2×47 Posts 
I know about them already. Restrict your comments to my proof.

20220411, 00:33  #6  
Apr 2020
1531_{8} Posts 
Very impressive  your proof still works if you set y and z equal to 1 or 2. That means you've managed to prove the Generalized Beal Conjecture:
Quote:


20220411, 02:44  #7  
"Curtis"
Feb 2005
Riverside, CA
1575_{16} Posts 
Quote:
Neat! 

20220411, 02:56  #8 
"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
DF9_{16} Posts 
If we allow one of the three exponents be 2 (but of course cannot be 1), the other two exponents must be >= 3, do there exist infinitely many solutions other than 2^3+1^n=3^2?

20220411, 03:10  #9 
If I May
"Chris Halsall"
Sep 2002
Barbados
29B8_{16} Posts 
Dude... Why do you pollute other's threads? Is it not enough to simply talk to yourself?

20220411, 03:14  #10 
If I May
"Chris Halsall"
Sep 2002
Barbados
2^{3}·3·5·89 Posts 
Is there actually something there?
It would be an excellent example of an outside idea being interjected if there was. I'm (clearly) unqualified to do anything but stupidly ask. But... I would welcome an answer from those who /actually/ know how this stuff works. Rather than the usual noise... 
20220411, 05:26  #11 
Jun 2003
5,407 Posts 

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