20070706, 06:51  #1 
May 2004
2^{2}·79 Posts 
Loud thinking on irregular primes
The relevant numerator of an irregular prime which IS NOT a Mangammal
prime has the form 3^n2.This can easily be identified, on pari, by {p(n)=(3^n2)/p'} where p' stands for irregular prime which is not a Mangammal prime.The required number is the only integer when we print p(n) for n=1,p'1. Further observations to be continued. A.K.Devaraj 
20070707, 05:12  #2  
May 2004
316_{10} Posts 
Quote:


20070709, 04:00  #3  
May 2004
474_{8} Posts 
Loud thinking on iregular primes
Quote:
What can we say about the numerator of Bernoulli numbers involving iMangammalirregular primes?Its shape is neither 2^n1 nor that of 3^n2. I will revert to this later, A.K.Devaraj 

20070719, 05:45  #4  
May 2004
2^{2}×79 Posts 
Loud Thinking on Irregular primes
Quote:
A.K.Devaraj 

20070725, 03:01  #5  
May 2004
2^{2}×79 Posts 
Loud Thinking on irregular primes
Quote:
Bernoulli numbers we come across Mangammal composites (A 119691OEIS).The numerator of Bernoulli numbers does not permit irregular Mangammal composites. A.K.Devaraj 

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