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Old 2021-08-12, 17:42   #1
ixfd64
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"Danny"
Dec 2002
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Default Prime95 startup delay

Prime95 always waits a short time before doing work when the computer starts up. I've noticed that the number of seconds is not the same every time. So I'm a little curious:

1. How is the amount of time determined?

2. Is there a way to tell Prime95 to immediately start doing work on startup?
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Old 2021-08-12, 18:48   #2
S485122
 
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"Jacob"
Sep 2006
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Look for "delay" in undoc.txt

In other words RTFormidableM ;-)

Last fiddled with by S485122 on 2021-08-12 at 18:49
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Old 2021-08-12, 18:48   #3
Uncwilly
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From undoc.txt
Quote:
The program normally will not start any calculation until 90 seconds after
a reboot. This is done so that your normal boot up procedure can be as
fast as possible. You can control how long this delay is by adding this
line to prime.txt, where n is the number of seconds to sleep:
BootDelay=n

Some machines report much better timings if the worker threads stagger
their starts. This was first noticed on Core i7 machines running Windows.
Presumably staggering starts improves timings due to each worker allocating
contiguous memory. You can control how long the program waits between
starting each worker. In prime.txt, enter:
StaggerStarts=n
where n is the number of seconds to wait. The default is 5 seconds.
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Old 2021-08-12, 19:04   #4
ixfd64
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Thanks. I was searching for "startup" in undoc.txt but didn't realize it says "boot up" instead.
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Old 2021-08-12, 19:06   #5
Uncwilly
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I searched "delay"

Last fiddled with by Uncwilly on 2021-08-12 at 19:07
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Old 2021-08-12, 21:30   #6
moebius
 
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I think the delay function makes sense because the Windows services are started first. What do you want to calculate in the fu ...... 90 seconds?
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