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#199 |
Quasi Admin Thing
May 2005
7·137 Posts |
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R16 is at n=360K, nothing found, continuing happily
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#200 |
Quasi Admin Thing
May 2005
7·137 Posts |
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7673*16^366247-1 is prime, unfortunantly it doesn't seem to prime k=7673 for b=256.
If anyone can tell me how this prime can also make 7673*256^n-1 prime, I'm more than happy to know. It appears that there could be a little to premature assumption that once b=16 primes k=7673 it also automatically primes k=7673 for b=256, wich would be correct if n was even, since the transformation requires a division of n by 2, in order for a b=16 number to be able to transform into a b=256 number. If there is something I'm missing, please enlighten me, but it could as far as I'm concerned be that a condition has to be added, like forinstance n having to be equal and not odd or however it would be translated ![]() Overall, does this mean, that k's we thought were searched by SOB, PSP and TRP in fact really hasn't been completely checked to that n-value? Does this mean that k's that has been assumed primed by a lower base prime in fact isn't primed when all comes to all? Anyway at least 1 k less so only 199 k's remain for the base=2 and powers of base=2 conjectures ![]() |
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#201 |
Jan 2006
Hungary
22·67 Posts |
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[QUOTE=KEP;360645]7673*16^366247-1 is prime, unfortunantly it doesn't seem to prime k=7673 for b=256.
I like that 7673 is prime too. Too bad 366247 isn't. Willem. |
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#202 | |
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
17·251 Posts |
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256/16 = 2^4 16^(4n) = 256^n k*16^(4n)-1 = k*256^n-1 What this means: If the n in base 16 is divisible by 4, then it also makes a prime in base 256. Since I can see that this n is odd, it does not make a prime in any base above 16. Last fiddled with by Mini-Geek on 2013-11-29 at 19:23 |
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#203 | |
Quasi Admin Thing
May 2005
7·137 Posts |
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![]() Sorry for any inconvenience, I guess I confused myself a little ![]() |
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#204 |
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
17·251 Posts |
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I think I did that too. 16^(4n) = 256^n is not true, this is (thanks Wikipedia):
16^(2n) = (16^2)^n = 256^n Part of my conclusion was still correct though: the fact that n is odd means that it's not a base 256 prime. Last fiddled with by Mini-Geek on 2013-11-29 at 20:49 |
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#205 |
May 2007
Kansas; USA
282B16 Posts |
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Nice prime Kenneth. It's too bad that n was not even to make a R256 prime. I have now reflected R256 k=7673 at n=183K, close enough to the depth that you reached base 256. I also have removed it as reserved by this drive. Effectively it's just lumped in with "other k's" now.
Last fiddled with by gd_barnes on 2013-11-30 at 00:22 |
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#206 | |
Quasi Admin Thing
May 2005
7×137 Posts |
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![]() Who knows, maybe I'll be able to find a Top1000 prime next time ![]() |
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#207 |
Quasi Admin Thing
May 2005
7·137 Posts |
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I missed an update due to private real life commitments
![]() R16 is at n=400K, nothing new found, continuing happily ![]() |
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#208 |
Quasi Admin Thing
May 2005
7·137 Posts |
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R16 is at n=420K. Nothing new found. Continuing happily.
If no further primes is found I expect the entire base to be at n=>500K around 19th of february 2014 ![]() Next status will be around January 11th, since it appears to take approximately 13 days to climb 20K n's... Regards Kenneth |
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#209 |
Quasi Admin Thing
May 2005
11101111112 Posts |
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Another prime found
![]() k=3620 eliminates 2 unprimed k's, since 3620*16^435506-1 also transforms into 3620*256^217753-1 ![]() So this time I was lucky and eliminated 2 k's in stead of 1 k. On a sidenote, this is my first prime to enter the "Short list" ![]() Status is currently all remaining 12 k's is tested to n=435000 ![]() Kenneth |
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