20131124, 18:48  #199 
Quasi Admin Thing
May 2005
7·137 Posts 
R16 is at n=360K, nothing found, continuing happily

20131129, 18:43  #200 
Quasi Admin Thing
May 2005
7·137 Posts 
7673*16^3662471 is prime, unfortunantly it doesn't seem to prime k=7673 for b=256.
If anyone can tell me how this prime can also make 7673*256^n1 prime, I'm more than happy to know. It appears that there could be a little to premature assumption that once b=16 primes k=7673 it also automatically primes k=7673 for b=256, wich would be correct if n was even, since the transformation requires a division of n by 2, in order for a b=16 number to be able to transform into a b=256 number. If there is something I'm missing, please enlighten me, but it could as far as I'm concerned be that a condition has to be added, like forinstance n having to be equal and not odd or however it would be translated Overall, does this mean, that k's we thought were searched by SOB, PSP and TRP in fact really hasn't been completely checked to that nvalue? Does this mean that k's that has been assumed primed by a lower base prime in fact isn't primed when all comes to all? Anyway at least 1 k less so only 199 k's remain for the base=2 and powers of base=2 conjectures 
20131129, 19:16  #201 
Jan 2006
Hungary
2^{2}·67 Posts 
[QUOTE=KEP;360645]7673*16^3662471 is prime, unfortunantly it doesn't seem to prime k=7673 for b=256.
I like that 7673 is prime too. Too bad 366247 isn't. Willem. 
20131129, 19:20  #202  
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
17·251 Posts 
Quote:
256/16 = 2^4 16^(4n) = 256^n k*16^(4n)1 = k*256^n1 What this means: If the n in base 16 is divisible by 4, then it also makes a prime in base 256. Since I can see that this n is odd, it does not make a prime in any base above 16. Last fiddled with by MiniGeek on 20131129 at 19:23 

20131129, 20:30  #203  
Quasi Admin Thing
May 2005
7·137 Posts 
Quote:
Sorry for any inconvenience, I guess I confused myself a little 

20131129, 20:45  #204 
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
17·251 Posts 
I think I did that too. 16^(4n) = 256^n is not true, this is (thanks Wikipedia):
16^(2n) = (16^2)^n = 256^n Part of my conclusion was still correct though: the fact that n is odd means that it's not a base 256 prime. Last fiddled with by MiniGeek on 20131129 at 20:49 
20131130, 00:07  #205 
May 2007
Kansas; USA
282B_{16} Posts 
Nice prime Kenneth. It's too bad that n was not even to make a R256 prime. I have now reflected R256 k=7673 at n=183K, close enough to the depth that you reached base 256. I also have removed it as reserved by this drive. Effectively it's just lumped in with "other k's" now.
Last fiddled with by gd_barnes on 20131130 at 00:22 
20131130, 20:49  #206  
Quasi Admin Thing
May 2005
7×137 Posts 
Quote:
Who knows, maybe I'll be able to find a Top1000 prime next time 

20131216, 15:21  #207 
Quasi Admin Thing
May 2005
7·137 Posts 
I missed an update due to private real life commitments but...
R16 is at n=400K, nothing new found, continuing happily 
20131229, 14:40  #208 
Quasi Admin Thing
May 2005
7·137 Posts 
R16 is at n=420K. Nothing new found. Continuing happily.
If no further primes is found I expect the entire base to be at n=>500K around 19th of february 2014 Next status will be around January 11th, since it appears to take approximately 13 days to climb 20K n's... Regards Kenneth 
20140109, 17:40  #209 
Quasi Admin Thing
May 2005
1110111111_{2} Posts 
Another prime found
k=3620 eliminates 2 unprimed k's, since 3620*16^4355061 also transforms into 3620*256^2177531 So this time I was lucky and eliminated 2 k's in stead of 1 k. On a sidenote, this is my first prime to enter the "Short list" Status is currently all remaining 12 k's is tested to n=435000 Kenneth 
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