20120306, 19:39  #1 
"Matthew Anderson"
Dec 2010
Oregon, USA
2·5·59 Posts 
Prime Constellations
I have been developing a java application to find prime constellations. Constelations of length are twin primes. Constellations of length 3 have one of two patterns [0,2,6] or [0,4,6]. More can be found on a power point presentation at 
https://sites.google.com/site/mattc1anderson/home1 I'm hoping that some people who read this post will download the application, and search for constellations. There is a .bat file in the src directory. Let me know if there are questions or comments. Constellations of lenght 20 have not been found yet. You can make history and be the first. 
20120306, 19:44  #2 
"Matthew Anderson"
Dec 2010
Oregon, USA
1116_{8} Posts 
oops the .zip didn't attach

20120306, 20:57  #3 
Nov 2003
1110100011000_{2} Posts 

20120306, 22:22  #4 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}×131 Posts 

20120306, 22:33  #5  
Nov 2003
2^{3}·7^{2}·19 Posts 
Quote:
a biggest one. Constructing one of arbitrary size is not difficult. See, e.g. http://www.ieeta.pt/~tos/apc.html Now can we end this silly discussion please? 

20120306, 23:48  #6  
Jun 2003
2^{3}×3×193 Posts 
Quote:


20120307, 00:46  #7  
Nov 2003
7448_{10} Posts 
Quote:
call an admissible contellation that matters. It is what the mathematical community calls it. "actual primes" is an instance of a constellation. A constellation is a set of linear univariate POLYNOMIALS. e.g. [x, x+2, x+6]. Specifying an actual value for x gives an instance. Actually, under Schinzel's conjecture, the definition can be broadened to include nonlinear polynomials as well. (2) Allow me to point out that there are 25 primes less than 100. There are also 25 primes in [13, 113]. Each of these form "patterns". They are two different patterns [instances of admissible constellations] in an interval of length 100. Unfortunately, these are the only two such "patterns" that exist. There are only finitely many instances of a constellation of size 25 in an interval of length 100. To get infinitely many instances of a constellation of size 25 one needs an interval larger than 100. Offhand, I do not know exactly how big such an interval needs to be. It would not be a hard calculation. A. Schinzel proved this. He (and my ex) also showed that the largest admissible constellation in an interval of length 100 that occurs i.o. has size 23, not 25. Now can the newbies please get off this subject until they have actually studied it? Repeat after me: Google is my friend. Look up "BatemanHorn" as well. 

20120307, 01:10  #8  
Nov 2003
2^{3}·7^{2}·19 Posts 
Quote:
finitely often, they do not form an admissible constellation by definition. 

20120307, 06:22  #9  
"Richard B. Woods"
Aug 2002
Wisconsin USA
2^{2}·3·641 Posts 
Quote:
Suggested guideline: whenever you see that a new thread, by someone who's not a forum veteran, contains inexact terminology, skip it and go somewhere else, without posting any reply. Let some other forum member(s) take care of determining the meaning and straightening out the newbie's terminology. Later, when you come back and see that the terminology has been straightened out, contribute in one of the many ways in which you really do have superior competency. If a known forum veteran posts inexact terminology, then feel free to post a correction right away. 

20120307, 11:04  #10  
Nov 2003
2^{3}×7^{2}×19 Posts 
Quote:


20120307, 14:08  #11 
Bamboozled!
May 2003
Down not across
10011101100000_{2} Posts 

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