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2019-08-24, 01:06   #485
ixfd64
Bemusing Prompter

"Danny"
Dec 2002
California

2×17×67 Posts

Quote:
 Originally Posted by Madpoo I don't know who that user is, but if I ever meet him/her, I'll buy 'em a drink of their choice.
Someone said his forum name was "error." However, he has neither confirmed nor denied this.

2019-08-24, 01:33   #486
mathwiz

Mar 2019

6710 Posts

Quote:
 Originally Posted by Madpoo I don't know who that user is, but if I ever meet him/her, I'll buy 'em a drink of their choice.
How many GHz days must one accumulate in order for you to buy them a nice glass of Macallan 25?

2019-08-24, 14:15   #487
kriesel

"TF79LL86GIMPS96gpu17"
Mar 2017
US midwest

3·5·271 Posts

Quote:
 Originally Posted by mathwiz How many GHz days must one accumulate in order for you to buy them a nice glass of Macallan 25?
Apparently not more than 663000/year. See #17 at https://www.mersenne.org/report_top_500/
But madpoo did not state his requirements, which could be identifying and implementing and running a novel approach at scale.

Last fiddled with by kriesel on 2019-08-24 at 14:17

 2019-08-24, 20:15 #488 a1call     "Rashid Naimi" Oct 2015 Out of my Body 17·107 Posts As an alternative for getting a free drink, I have no doubt that Madpoo as well as many others (some might insist for the drink to be nonalcoholic) will be glad to pay for a drink if you can find a factor for M1277. Even, TJAOI hasn't given a factor for that yet, AFAIK. Last fiddled with by a1call on 2019-08-24 at 20:16
2019-08-24, 22:31   #489
lycorn

Sep 2002
Oeiras, Portugal

101011001002 Posts

Quote:
 Originally Posted by a1call Even, TJAOI hasn't given a factor for that yet, AFAIK.
Not even Ryan Propper...

2019-08-25, 05:32   #490
Serpentine Vermin Jar

Jul 2014

2·23·71 Posts

Quote:
 Originally Posted by kriesel Apparently not more than 663000/year. See #17 at https://www.mersenne.org/report_top_500/ But madpoo did not state his requirements, which could be identifying and implementing and running a novel approach at scale.
I also didn't specify drink size... hmm... I hadn't thought through some of the pricier drinks out there, but my "out" is that by "drink" I could be referring to as little as a teaspoon-full.

Would they serve such a tiny amount?

2019-08-31, 10:31   #491
LaurV
Romulan Interpreter

Jun 2011
Thailand

3×2,861 Posts

Quote:
 Originally Posted by a1call As an alternative for getting a free drink, I have no doubt that Madpoo as well as many others (some might insist for the drink to be nonalcoholic) will be glad to pay for a drink if you can find a factor for M1277.
I will buy a drink for whoever gets a factor of M1279. You won't argue for plus or minus two, would you?

2019-08-31, 10:47   #492
retina
Undefined

"The unspeakable one"
Jun 2006
My evil lair

25·173 Posts

Quote:
 Originally Posted by LaurV I will buy a drink for whoever gets a factor of M1279.
M1279 = (2^1279-1) * 1

There you go, both factors.

 2019-08-31, 12:55 #493 a1call     "Rashid Naimi" Oct 2015 Out of my Body 71B16 Posts Giving a factor for M1277 is easy as long as you don't ask for the decimal expansion $ GCD\left( \left( \sqrt {M1277}\backslash 1\right) !,M1277\right)$
2019-09-01, 12:51   #494
alpertron

Aug 2002
Buenos Aires, Argentina

1,319 Posts

Quote:
 Originally Posted by a1call Giving a factor for M1277 is easy as long as you don't ask for the decimal expansion $GCD\left( \left( \sqrt {M1277}\backslash 1\right) !,M1277\right)$
I think that if all prime factors of M1277 are less than its square root, the GCD will give you M1277.

2019-09-01, 13:58   #495
a1call

"Rashid Naimi"
Oct 2015
Out of my Body

181910 Posts

Quote:
 Originally Posted by alpertron I think that if all prime factors of M1277 are less than its square root, the GCD will give you M1277.
Looks like I was too quick at going and having a glass of orange juice.

Since it seems impossible to parse # in LaTeX how about:

GCD((sqrt(M1277)\1)#,M1277)

Would that fair any better?
Now only one of the factors can be in common if any are powers.
And since M1277 is not a primorial something must be uncommon.

ETA I realize that I was wrong and the primorial does not fair any better. Thanks for pointing that out.

Last fiddled with by a1call on 2019-09-01 at 14:23

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