20190103, 11:00  #1 
May 2007
Kansas; USA
26475_{8} Posts 
2019 project goals
Below are some goals for 2019 that CRUS can go for:
1. Prove 5 bases; completed 2019/06/25! 2. Search all bases with 1 k remaining (at n=200K) to n>=400K;completed 2019/10/23! 3. Search all bases with <= 5 k's remaining (at n=100K) to n>=200K; completed 2019/10/22! 4. Complete all bases with conjectured k < 100K to n=25K; completed 2019/07/22! If anyone has any that they would like to add, please feel free to post your thoughts. I'm confident that we can accomplish many or all of these goals. Any and all help is appreciated! Last fiddled with by gd_barnes on 20191023 at 19:54 Reason: update counts 
20190103, 11:05  #2 
May 2007
Kansas; USA
37×313 Posts 
Here are some 2019 top5000 primes goals proposed by Masser in the 2018 thread that we can shoot for:
100 top 3000 primes in 2019; completed 2019/12/07! 20 top 1000 primes in 2019; completed 2019/08/26! 5 top 200 primes in 2019; 3 primes to go. Last fiddled with by gd_barnes on 20191207 at 21:11 Reason: update counts 
20190626, 19:25  #3 
May 2007
Kansas; USA
37·313 Posts 
With the proof of S780, that makes 5 proofs for 2019. Goal #1 has now been completed!

20190627, 05:41  #4 
Dec 2011
After milion nines:)
2^{3}×3×67 Posts 

20190627, 06:23  #5 
Romulan Interpreter
"name field"
Jun 2011
Thailand
2·47·109 Posts 

20190627, 07:52  #6  
May 2007
Kansas; USA
11581_{10} Posts 
Quote:
Hmm... 10 * 743285478+1 = 11*41*1831*9001 Surely you are mistaken. Please use the exponentiation symbol. In all seriousness, it is more appropriate to allow people to post their own top5000 primes first in the forum, especially if it involves a proof. Otherwise you are stealing their thunder. Last fiddled with by gd_barnes on 20190627 at 08:04 

20190627, 08:45  #7  
Dec 2011
After milion nines:)
2^{3}·3·67 Posts 
Quote:


20190628, 01:44  #8  
"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2^{2}·11·83 Posts 
Quote:
6. Search all bases with 1 k remaining and this k is <= 12 to n>=1M; 7. Search all bases <= 300 with <= 25 k's remaining (at n=100K) to n>=200K. Last fiddled with by sweety439 on 20190628 at 01:48 

20190628, 08:45  #9 
May 2007
Kansas; USA
26475_{8} Posts 

20190722, 22:55  #10 
May 2007
Kansas; USA
11581_{10} Posts 
With the completion of S1018 to n=25K, goal #4 has been accomplished!

20190803, 15:19  #11 
"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
3652_{10} Posts 
Complete all bases with conjectured k <= 200K to n=25K;
Complete all bases with conjectured k <= 250K to n=10K; 
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