20201008, 10:40  #1046 
Nov 2016
2^{2}·691 Posts 

20201008, 10:41  #1047 
Nov 2016
ACC_{16} Posts 
The CK for S726 is known to be 10923176
The CK for R726 is known to be 12751579 
20201008, 10:41  #1048 
Nov 2016
101011001100_{2} Posts 
The CK for R690 is known to be 42053568
The CK for S690 is still running .... 
20201010, 21:28  #1049 
Nov 2016
ACC_{16} Posts 
S690 has CK = 395800653

20201010, 22:06  #1050  
Nov 2016
2^{2}·691 Posts 
Quote:
Base 2: None of SR2, SR4, SR8, SR16, SR32, SR64, SR128, SR512, SR1024 have generalized repunits remain. (note that the exponent of R128 k=16 is (32174)/7 = 459, and the corresponding prime is 2^32171, since 3217 is the smallest number in A000043 which is == 4 mod 7, and note that the exponent of R512 k=4 is (199372)/9 = 2215, and the corresponding prime is 2^199371, since 19937 is the smallest number in A000043 which is == 2 mod 9) Base 3: * For R243 k=81, the test limit is (22153034)/5 = 443059.8 (unfortunately, there are no known numbers in A028491 which are == 4 mod 5), but the true test limit may be larger, since Paul Bourdelais is searching generalized repunit (probable) primes for small bases (see top PRPs) Base 5: None of SR5, SR25, SR125, SR625 have generalized repunits remain. (note that the exponent of S625 k=125 is (673)/4 = 16, and the corresponding prime is (5^67+1)/6, since 67 is the smallest number in A057171 which is == 3 mod 4) Base 6: None of SR6, SR36, SR216 have generalized repunits remain. (note that the exponent of R216 k=36 is (292)/3 = 9, and the corresponding prime is (6^291)/5, since 29 is the smallest number in A004062 which is == 2 mod 3) Base 7: None of SR7, SR49, SR343 have generalized repunits remain. Base 10: None of SR10, SR100, SR1000 have generalized repunits remain. (note that the exponent of R10 k=100 is 192 = 17, and the corresponding prime is (10^191)/9, since 19 is the smallest number in A004023 which is > 2) Base 11: None of SR11, SR121 have generalized repunits remain. Base 12: None of SR12, SR144 have generalized repunits remain. Bases > 12: No bases with generalized repunits (k is rational power of b) other than k=1 remain, except R243 k=81, all Riesel bases <= 1024 with k=1 (which is equivalent to generalized repunits base b) remain are 185, 269, 281, 380, 384, 385, 394, 452, 465, 511, 574, 601, 631, 632, 636, 711, 713, 759, 771, 795, 861, 866, 881, 938, 948, 951, 956, 963, 1005, 1015, and the test limit is 100K by Michael Stocker 

20201010, 22:54  #1051 
Nov 2016
2^{2}·691 Posts 
1. Any k that obtains a full covering set in any manner from ALGEBRAIC factors will be excluded. In many instances, this includes k's where there is a partial covering set of numeric factors (or a single numeric factor) and a partial covering set of algebraic factors that combine to make a full covering set.
2. kvalues in the case in post https://mersenneforum.org/showpost.p...&postcount=265 will be excluded, since they have no possible primes but with no NUMERIC covering set, like the kvalues in the condition in #1. 3. All k below the lowest k found to have a NUMERIC covering set must have a prime including multiples of the base (MOB) but excluding the conditions in #1 and #2 above. 4. All n must be >= 1. Last fiddled with by sweety439 on 20201011 at 00:31 
20201010, 23:00  #1052  
Nov 2016
2^{2}·691 Posts 
Quote:
Also, the exponent of R27 k=9 is (712)/3 = 23, and the corresponding prime is (3^711)/2, since 71 is the smallest number in A028491 which is == 2 mod 3 Also, the exponent of S961 k=31 is (1091)/2 = 54, and the corresponding prime is (31^109+1)/32, since 109 is the smallest number in A126856 

20201010, 23:02  #1053  
Nov 2016
2^{2}×691 Posts 
Quote:
Sierpinski Riesel (format: b,the lowest k found such that (k*b^n+1)/gcd(k+1,b1) (+ for Sierpinski,  for Riesel) have a numeric covering set) 

20201011, 00:05  #1054 
Nov 2016
ACC_{16} Posts 
All n must be >= 1.
All MOB kvalues need an n>=1 prime (unless they have a covering set of primes, or make a full covering set with all or partial algebraic factors) MOB kvalues such that (k+1)/gcd(k+1,b1) (+ for Sierpinski,  for Riesel) is not prime are included in the conjectures but excluded from testing. Such kvalues will have the same prime as k / b. There are some MOB kvalues such that (k+1)/gcd(k+1,b1) (+ for Sierpinski,  for Riesel) is prime which do not have an easy prime with n>=1: GFN's and half GFN's: (all with no known primes) S2 k=65536 S3 k=3433683820292512484657849089281 S4 k=65536 S5 k=625 S6 k=1296 S7 k=2401 S8 k=256 S8 k=65536 S9 k=3433683820292512484657849089281 S10 k=100 S11 k=14641 S12 k=12 S13 k=815730721 S14 k=196 S15 k=225 S16 k=65536 Other k's: S2 k=55816: first prime at n=14536 S2 k=90646: no prime with n<=6.6M S2 k=101746: no prime with n<=6.6M S3 k=621: first prime at n=20820 S4 k=176: first prime at n=228 S5 k=40: first prime at n=1036 S6 k=90546 S7 k=21: first prime at n=124 S9 k=1746: first prime at n=1320 S9 k=2007: first prime at n=3942 S10 k=640: first prime at n=120 S24 k=17496: first prime at n=37938 S35 k=41650: first prime at n=6038 S59 k=3540: first prime at n=218 S75 k=5700: first prime at n=1636 S77 k=6006: no prime with n<=1728 S81 k=6480: first prime at n=5393 S155 k=310: no prime with n<=2K S333 k=1998: first prime at n=27900 R2 k=74: first prime at n=2552 R2 k=674: first prime at n=11676 R2 k=1094: first prime at n=652 R2 k=71444: first prime at n=98952 R2 k=340934: first prime at n=55272 R2 k=351134: no prime with n<=6.63M R2 k=381854: first prime at n=72288 R2 k=478214: no prime with n<=6.63M R4 k=1524: first prime at n=1994 R4 k=19464: no prime with n<=3.3M R5 k=26000: first prime at n=6112 R5 k=84200: first prime at n=9356 R5 k=138800: first prime at n=4512 R6 k=103536: first prime at n=6474 R6 k=106056: first prime at n=3038 R7 k=679: no prime with n<=3K R10 k=40: first prime at n=14 R10 k=100: first prime at n=17 R10 k=230: first prime at n=60 R10 k=450: first prime at n=11958 R10 k=2650: first prime at n=252 R10 k=16750: no prime with n<=200K R10 k=78880: no prime with n<=5K R11 k=308: first prime at n=444 R14 k=2954: no prime with n<=50K R15 k=2940: first prime at n=13254 R15 k=8610: first prime at n=5178 R15 k=300870: first prime at n=156608 R18 k=324: first prime at n=25665 R21 k=84: first prime at n=88 R23 k=230: first prime at n=6228 R24 k=1824: first prime at n=138568 R24 k=18504: first prime at n=48462 R27 k=594: first prime at n=36624 R31 k=124: first prime at n=1116 R31 k=69998: first prime at n=13618 R40 k=520: no prime with n<=1K R40 k=209960: no prime with n<=100K R42 k=1764: first prime at n=1317 R48 k=384: no prime with n<=200K R66 k=1056: no prime with n<=1K R78 k=7800: no prime with n<=1K R88 k=3168: first prime at n=205764 R96 k=9216: first prime at n=3341 R120 k=4320: no prime with n<=1K R126 k=15750: first prime at n=1495 R210 k=44100: first prime at n=19817 R306 k=93636: first prime at n=26405 R396 k=156816: no prime with n<=50K R591 k=1182: first prime at n=1190 R598 k=357604: no prime with n<=30K R706 k=497730: first prime at n=4734 R738 k=401402628: first prime at n=3490 R777 k=602952: first prime at n=4997 R789 k=490546548: first prime at n=1314 R815 k=663410: first prime at n=1472 R903 k=735498918: first prime at n=2736 R916 k=838140: first prime at n=3887 R954 k=1908: first prime at n=1476 R976 k=1952: first prime at n=1924 R982 k=963342: first prime at n=2484 R1102 k=2204: first prime at n=52176 R1297 k=2594: first prime at n=19839 R1360 k=2720: first prime at n=74688 Last fiddled with by sweety439 on 20201018 at 08:56 
20201011, 00:24  #1055 
Nov 2016
2^{2}·691 Posts 
Multiples of the base (MOB) are NOT excluded from the conjectures. They are excluded from the TESTING of the conjectures if (k+1)/gcd(k+1,b1) (+ for Sierpinski,  for Riesel) is composite. Previously they were shown as being excluded from the conjectures.
#2 is an important distinction if algebraic factors or MOB take priority. That is, if k=4*b is eliminated because it is a MOB and k=4 has algebraic factors to make a full covering set, which of the two takes priority for k=4*b since it would also have algebraic factors to make a full covering set? The answer is algebraic factors take priority because k=4 cannot ever have a prime and so k=4*b must still be accounted for. SO: k=4*b has to be shown with algebraic factors because it too cannot ever have a prime. This is certainly mathematical pickiness but to account for all k's, you can't just say a k is eliminated from the conjecture because it is a MOB and (k+1)/gcd(k+1,b1) (+ for Sierpinski,  for Riesel) is composite. The k still remains; it's just not shown as remaining or tested because k/b should eventually (or already has) yield the same prime. But if k/b can never have a prime than you must account for k. Don't worry if this doesn't make much sense. It only comes into play if a base has some k's with algebraic factors to make a full covering set and the conjecture is large enough where k*b comes in below the conjecture. This is a small percentage of bases; very small on the Sierpinski side. Last fiddled with by sweety439 on 20201011 at 00:24 
20201011, 16:35  #1056 
Nov 2016
5314_{8} Posts 
kvalues that are a multiple of base (b) and where (k+1)/gcd(k+1,b1) (+ for Sierpinski,  for Riesel) is not prime are included in the conjectures but excluded from testing, since such kvalues will have the same prime as k / b.
However, kvalues that are a multiple of base (b) and where (k+1)/gcd(k+1,b1) (+ for Sierpinski,  for Riesel) is prime are included from testing since the exponent n must be >=1 (n can be 1, but cannot be 0 or 1 or 2 or ...), and the same prime n=1 for k / b would be n=0 for this k but n must be >=1 hence it is not allowed so this k must continue to be searched. (of course, kvalues that are not a multiple of base (b) are included from testing) Thus, for S3, k = 42, 45, 57, 60, 66 and 72 are included from testing since although 42, 45, 57, 60, 66 and 72 are multiples of 3, but 42+1, (45+1)/2, (57+1)/2, 60+1, 66+1 and 72+1 are primes. However, k = 48, 51, 54, 63, 69 and 75 are excluded from testing since 48, 51, 54, 63, 69 and 75 are multiples of 3, and 48+1, (51+1)/2, 54+1, (63+1)/2, (69+1)/2 and (75+1)/2 are not primes. Besides, for R3, k = 42, 48, 54, 60, 63, 72 and 75 are included from testing since although 42, 48, 54, 60, 63, 72 and 75 are multiples of 3, but 421, 481, 541, 601, (631)/2, 721 and (751)/2 are primes. However, k = 45, 51, 57, 66 and 69 are excluded from testing since 45, 51, 57, 66 and 69 are multiples of 3, and (451)/2, (511)/2, (571)/2, 661 and (691)/2 are not primes. Note: Since 1 is not prime, thus for R3, k = 3 is excluded from testing. ((31)/2 = 1) However, since 2 is prime, thus for S3, k = 3 is included from testing. ((3+1)/2 = 2) 
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