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#1 |
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
426710 Posts |
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http://www.primenumbersformula.com/
![]() In classic crank fashion, it's hard to understand what he's trying to say, but I'm pretty sure he claims to have formulas for generating primes and Mersenne primes, has proved the infinitude of twin primes, and has solved the Riemann hypothesis. |
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#2 | |||
"Richard B. Woods"
Aug 2002
Wisconsin USA
170148 Posts |
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Quote:
I do see references to "the solution of Riemann Zeta equation" and "solution to Riemann zeta equation (http://www.primenumbersformula.com/a...s/image038.gif)", but those are not at all the same as claiming a proof of the Riemann Hypothesis. (The Riemann Hypothesis is a conjecture about a common property of all nontrivial zeros (solutions) of the zeta function.) At least he credits GIMPS properly, though without a single link (even in his "Favorite Links" section!) to us: Quote:
Last fiddled with by cheesehead on 2009-03-03 at 19:46 Reason: removed quibble about adaptation. |
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#3 |
Aug 2006
598510 Posts |
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His claim that generating a formula for the prime is a "2300-years old unsolvable problem" is a little wacky. It's been solved... over and over and over.
Last fiddled with by CRGreathouse on 2009-03-03 at 20:17 |
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#4 |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
5×1,223 Posts |
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But the formula is posted there on the page in plain view. I would think it would by easy to find a non-prime generated by the formula.
Although strange how it says "unsolvable problem" and then goes on to give a solution! |
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#5 |
6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
19×499 Posts |
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Correct me if I am wrong, but, doesn't this simplify to:
H(m)=(2m+1)1 ? |
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#6 |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
10111111000112 Posts |
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Well, at this stage I am too lazy to program anything up to check it, but in the website it shows this sequence "3,5,7,2,11,13,2,17,19, ..." So assuming they applied their formula correctly (I Haven't checked), then it can't be a simple 2m+1.
Last fiddled with by retina on 2009-03-04 at 01:38 |
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#7 | |
"Ben"
Feb 2007
1101010010112 Posts |
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Here's excel code: Code:
=2*((2*B16+1)/2)^(FLOOR((2*B16+1)/(FACT(2*B16)+1)*FLOOR((FACT(2*B16)+1)/(2*B16+1),1),1)) |
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#8 |
Feb 2006
Denmark
111001102 Posts |
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You probably have rounding errors. In PARI/GP the formula is:
H(m) = 2*((2*m+1)/2)^floor((2*m+1)/((2*m)!+1)*floor(((2*m)!+1)/(2*m+1))) The formula is correct but useless. It uses Wilson's theorem and the floor function to give: H(m) = 2m+1, if 2m+1 is prime = 2, otherwise Wilson's theorem says 2m+1 is prime iff (2m)!+1 is divisible by 2m+1. Then floor((2*m+1)/((2*m)!+1)*floor(((2*m)!+1)/(2*m+1))) becomes 1 when 2m+1 is prime, and 0 when it's composite. |
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#9 |
Aug 2006
32·5·7·19 Posts |
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The formula looks fine to me -- it should generate the odd primes in order, with 2 replacing each odd composite.
Edit: Jens Anderson beat me to it. Last fiddled with by CRGreathouse on 2009-03-04 at 02:59 |
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#10 | ||
"Richard B. Woods"
Aug 2002
Wisconsin USA
769210 Posts |
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Quote:
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#11 |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
5×1,223 Posts |
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It seems to me that this is more of prime testing formula than a function. They have taken a prime testing formula and manipulated the algebra to give you back the original prime you tested if it passes or 2 if it fails. It would be easy to change the '2' to any other number (like pi or e or i) to give a fixed value when the test fails.
Hmm, that has given me an idea ... Last fiddled with by retina on 2009-03-04 at 10:44 |
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