Simple Arithmetic!

mfgoode · 2007-04-21, 17:09

Is this equation correct ?

2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ?

Mally

mfgoode · 2007-04-22, 04:31

Moderator the time marked for my post is 3hrs before I got on my computer and posted this message an hour or so later!

Something wrong with the software? The next post on has been put later than my post and hence given preference.

Mally

P.S. it has been immediately corrected during writing of this reply.

m_f_h · 2007-04-22, 04:53

Quote:

Originally Posted by mfgoode

Is this equation correct ?
2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ?
Mally

It depends on what the "." and "*" mean (in regular expressions (regexp) the former represent an arbitrary character, in DOS command lines the latter represent an arbitrary sequence of characters ;
finally [ ] might be the "Gaussklammer"...

retina · 2007-04-22, 08:11

One side is sqrt(2) larger than the other. Is that supposed to be a puzzle or just something you don't understand?

victor · 2007-04-22, 11:06

Quote:

Originally Posted by mfgoode

Is this equation correct ?

2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ?

Mally

Yes it is.
If . and * mean multiplication, and sq, rt are variable.
2 x y (2/3) = x y 2 (2/3) ...

S485122 · 2007-04-22, 11:26

If . and * are multiplication what is the meaning of the concatenation of the two in the first part of the first term : "2.*sq".

In the formula I see a lot of (intentional ?) inconsistencies : "2." versus "2*", "rt" versus "rt."

My first intention was asking what the ".", the "*" and "sq.rt" meant. But then I realised it could be the core of the riddle.

Orgasmic Troll · 2007-04-22, 16:53

Quote:

Originally Posted by mfgoode

Moderator the time marked for my post is 3hrs before I got on my computer and posted this message an hour or so later!

Something wrong with the software? The next post on has been put later than my post and hence given preference.

Mally

P.S. it has been immediately corrected during writing of this reply.

.

mfgoode · 2007-04-23, 03:41

Quote:

Originally Posted by m_f_h

It depends on what the "." and "*" mean (in regular expressions (regexp) the former represent an arbitrary character, in DOS command lines the latter represent an arbitrary sequence of characters ;
finally [ ] might be the "Gaussklammer"...

Sorry for the confusion.

2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ?

means 2 multiplied by the square root of 2/3 = square root of 2 multiplied by 2/3. So in one side the 2 is outside the square root on the other 2 is inside the square root.

* is multiplication, []are brackets, Its not the Gaussklammer.
'.' is full stop.
It is not a riddle! Its just a maths curiosity which looks odd and that it is wrong but it is right.

Mally

mfgoode · 2007-04-23, 03:46

Quote:

Originally Posted by Orgasmic Troll

.

I had my launchcast radio on, on 'My Station' and believe it or not that guy on the keyboard was actually keeping in time to it. Amazing!

Mally

Orgasmic Troll · 2007-04-23, 05:26

so you're claiming that $(2)( \sqrt{\frac{2}{3}}) = \sqrt{(2) (\frac{2}{3})}$ ?

$(2)( \sqrt{\frac{2}{3}}) = \sqrt{(4) (\frac{2}{3})} \neq \sqrt{(2) (\frac{2}{3})}$

mfgoode · 2007-04-23, 08:38

Yes.

The version you have given is totally wrong

Mally

2007-04-21, 17:09	#1
mfgoode Bronze Medalist Jan 2004 Mumbai,India 2²·3³·19 Posts	Simple Arithmetic! Is this equation correct ? 2.sq.rt (2/3) = sq.rt. [2(2/3)] ? Yes or No ? Mally

2007-04-22, 04:31	#2
mfgoode Bronze Medalist Jan 2004 Mumbai,India 2²·3³·19 Posts	Wrong local time! Moderator the time marked for my post is 3hrs before I got on my computer and posted this message an hour or so later! Something wrong with the software? The next post on has been put later than my post and hence given preference. Mally P.S. it has been immediately corrected during writing of this reply. Last fiddled with by mfgoode on 2007-04-22 at 04:33

2007-04-23, 08:38	#11
mfgoode Bronze Medalist Jan 2004 Mumbai,India 804₁₆ Posts	Yes. The version you have given is totally wrong Mally Last fiddled with by mfgoode on 2007-04-23 at 08:41

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2007-04-22, 08:11	#4
retina Undefined "The unspeakable one" Jun 2006 My evil lair 29·211 Posts	One side is sqrt(2) larger than the other. Is that supposed to be a puzzle or just something you don't understand?

2007-04-22, 11:26	#6
S485122 Sep 2006 Brussels, Belgium 1660₁₀ Posts	If . and * are multiplication what is the meaning of the concatenation of the two in the first part of the first term : "2.sq". In the formula I see a lot of (intentional ?) inconsistencies : "2." versus "2", "rt" versus "rt." My first intention was asking what the ".", the "*" and "sq.rt" meant. But then I realised it could be the core of the riddle.

2007-04-23, 05:26	#10
Orgasmic Troll Cranksta Rap Ayatollah Jul 2003 281₁₆ Posts	so you're claiming that $(2)( \sqrt{\frac{2}{3}}) = \sqrt{(2) (\frac{2}{3})}$ ? $(2)( \sqrt{\frac{2}{3}}) = \sqrt{(4) (\frac{2}{3})} \neq \sqrt{(2) (\frac{2}{3})}$