20060120, 12:16  #265 
Jul 2005
2×193 Posts 
Excellent, thought I'd be missing something.
n=56 still not done yet, can't be far off as I've got 266121 so far and the estimate was 280214. After that I'll be finding all of the previously found Octoproths and saving the records out into separate files. If I get time over the weekend I'll fix the DB and upload them and open up the cgibin to view/download them. So much to do, so little time... 
20060120, 16:03  #266 
Jul 2005
182_{16} Posts 
n=56 complete!
OK, n=56 is complete!
Estimate was 280214. Final count after isprime() PARI checking script: 285415 2^n = 72057594037927936 so I used a kmax of 72060T. Output: n=56, kmin=0T, kmax=72060T, version=5.0, here T=10^12 Starting the sieve... Using the first 11 primes to reduce the size of the sieve array [285415 lines removed] The sieving is complete. Number of Prp tests=1503700301 Time=187990 sec. So that's 2 days, 4 hours, 13 minutes, 10 seconds. That's the end of it, not going to start n=57, there are too many of them! 
20060124, 21:51  #267 
"Robert Gerbicz"
Oct 2005
Hungary
2^{2}×3×7×19 Posts 
new octo program!
In this program now there is no limitation on k value. I've tried all three optimization flags ( among O1, O2, O3 ) and O1 was the fastest ( try this one ). Just to see that the program correctly identify large k values, I've tried:
C:\>octo_6_0 72 10000000T 10000010T You can also find the k n values in results_octo.txt file ( These are 3probable primes ) n=72, kmin=10000000T, kmax=10000010T, version=6.0, here T=10^12 Starting the sieve... Using the first 8 primes to reduce the size of the sieve array 10000002989467112895 72 10000000479372125565 72 10000007742413127075 72 10000007506574893605 72 10000009359875458875 72 10000007773909145265 72 10000003164141619125 72 10000001353327652625 72 10000000828720374885 72 10000008277743037575 72 10000002428249499645 72 10000001785208783145 72 10000003434544089015 72 10000007626546970445 72 10000002610159188375 72 The sieving is complete. Number of Prp tests=591004 Time=539 sec. Correct! These k values are larger than 10^19 ( >2^60, previous limit ). I've also modified some parts in the code. See the attachment for the c code. Or download the exe for windows from: http://www.robertgerbicz.tar.hu/octo_6_0.exe 
20060126, 20:21  #268 
Jun 2003
Suva, Fiji
2^{3}×3×5×17 Posts 
Still mystified
I am still mystified why some values of n give many more octoproths and dodecaproths than others. I am also mystified as to why Robert and others are able to forecast the number of octos. If it was variable k I would understand, (modular arithmetic), but I am a bit stumped here.
Can someone furnish a non code explanation? Regards Robert Smith 
20060126, 21:07  #269  
"Robert Gerbicz"
Oct 2005
Hungary
2^{2}×3×7×19 Posts 
number of octoproths for n
Quote:
By prime number theorem a random k integer is prime by about 1/log(k) probability, because there are about k/log(k) prime numbers up to k. If we are searching for octoproths then we are searching 8 prime numbers where k<2^n, so if these numbers are independent then there are about 2^n/(log(2^n)^4*log(2^(2*n))^4)=2^n/((n*log(2))^8*16) octoproths ( because 4 forms are about 2^n in almost all cases the other 4 forms are much larger: about 2^(2*n) ) But these numbers are not independent! We have to remultiple by some factors, count the remainders modulo p..., this factor for each n is the weight of n ( for octoproth ) More information at: http://www.ltkz.demon.co.uk/ktuplets.htm#mathbg See the famous HardyLittlewood Prime ktuple Conjecture. Actually an octoproth isn't a ktuplet but it is very similar to that. 

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