20181201, 23:18  #12  
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
2^{4}×11×53 Posts 
Quote:
Code:
? m=20*q+1 ? ((2*m+1)*(10*m+1)*(16*m+1)1)/(2*m) 64000*q^2 + 8520*q + 280 ? ((2*m+1)*(10*m+1)*(16*m+1)1)/(10*m) 12800*q^2 + 1704*q + 56 ? ((2*m+1)*(10*m+1)*(16*m+1)1)/(16*m) 8000*q^2 + 1065*q + 35 \\ > all three divide 

20181202, 02:51  #13 
Aug 2006
5972_{10} Posts 
What does Václav Šimerka prove there, Serge?

20181202, 05:17  #14 
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
2^{4}·11·53 Posts 
I don't read Czech, sadly, only numbers... but this fragment on page 224 seems interesting...

20181202, 09:27  #15  
"Forget I exist"
Jul 2009
Dumbassville
2^{6}×131 Posts 
Quote:
Quote:


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