![]() |
![]() |
#1 |
I quite division it
"Chris"
Feb 2005
England
31×67 Posts |
![]()
Is the maths here wrong or am I going mad (it could be both of course):
Bloodhound: Superwheels for supersonic car go into production Last fiddled with by Batalov on 2015-03-16 at 16:42 Reason: (link) |
![]() |
![]() |
![]() |
#2 | |
"Kieren"
Jul 2011
In My Own Galaxy!
22×2,539 Posts |
![]() Quote:
http://www.bbc.co.uk/news/science-environment-31845234 |
|
![]() |
![]() |
![]() |
#3 |
∂2ω=0
Sep 2002
República de California
3×53×73 Posts |
![]()
Fascinating stuff about the high-tech disc wheels - thx for the link(s).
|
![]() |
![]() |
![]() |
#4 |
"Curtis"
Feb 2005
Riverside, CA
52×11×17 Posts |
![]()
Which maths are you doubting?
radial (centripetal) acceleration = r * (angular velocity)^2. 170 rev/sec * 2pi = 1068 radians/sec. r = 45cm, so a = 510000, or 50000g after some rounding to be conservative. 10500 RPM was also claimed; divide by 60 to get the same 170 rev/sec (again, rounded for journalistic use). A number not cited in the article: 1068 rad/sec *r = 480 m/sec linear velocity of car. But a m/sec is 2.23 MPH, so 1070 MPH. That's only a little higher than the target speed record, which is averaged over a mile or more. |
![]() |
![]() |
![]() |
#5 |
I quite division it
"Chris"
Feb 2005
England
31×67 Posts |
![]()
I was out by a factor of ten for some reason.
![]() |
![]() |
![]() |