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 2008-09-30, 21:39 #1 Prime95 P90 years forever!     Aug 2002 Yeehaw, FL 7×1,069 Posts Odd email I received this email today. The number is not prime, anyone have other ideas? A senior ranking Non Commissioned Officer here in Iraq has given a group of us a number and no clues to as to what it is. A few of us feel it is something to do with it being a prime number. We are all not math geniuses. So here is where I turn to you for your expert opinion. The number is: 20120121122515626145776622735224615338815731191617 Please assist in any way you can. Thanks for your help.
 2008-09-30, 21:43 #2 Mini-Geek Account Deleted     "Tim Sorbera" Aug 2006 San Antonio, TX USA 426710 Posts BTW its factorization is: 20120121122515626145776622735224615338815731191617 = 479 * 133289810174980013 * 315136079611630044400219008571 Just from looking at the number I see it has a quite high number of pairs of digits (...1122...776622 etc.), but in a number of this length, that could be purely coincidental.
 2008-10-01, 03:52 #3 roger     Oct 2006 1000001002 Posts Well, looking at it as a substitution cipher, I get the possibilities: Code: 20120 tat 1211225 lkve lkby laly lalbe laave auly auve abkve abkbe abaly abaave abalbe 15 o ae 6 f 26 z bf 14 n ad 5 e 7 g 7 g 6 f 22 v bb 7 g 3 c 5 e 224 vd bx bbd 6 f 15 o ae 3 c 3 c 8 h 8 h 15 o ae 7 g 3 c 119 ki 16 p af 17 q ag which seems like gibberish in English, though isn't necessarily English even if it is a cipher... I initially thought it could be a cipher because of the many strings of 2x and 1x in the first half. Within the number, only 2012012112251562614577662273522461533881 120121122515626145776622735224615338815731191617 6145776622735224615338815731191617 617 17 7 are prime (working from the beginning to end or vice versa, deleting one digit at a time). This is quite a bit lower than most that I've seen (ie from the Homeprime patterns). I don't know if this is helpful at all, but good luck with it
2008-10-01, 22:58   #4
Orgasmic Troll
Cranksta Rap Ayatollah

Jul 2003

10100000012 Posts

Quote:
 Originally Posted by Mini-Geek BTW its factorization is: 20120121122515626145776622735224615338815731191617 = 479 * 133289810174980013 * 315136079611630044400219008571 Just from looking at the number I see it has a quite high number of pairs of digits (...1122...776622 etc.), but in a number of this length, that could be purely coincidental.
back-of-the-envelope calculation:

50 digit number has 49 pairs of digits, the probability that a pair of digits is comprised of the same digit is 10%, so we expect to see about 5 pairs (which includes something like ...12223... counting as 2 pairs).

I count 9 pairs, which is 1.95 standard deviations away (using the binomial distribution), and I think that's right under the 95% confidence interval, so I'd say it's not extraordinary, but I wouldn't be surprised if someone else came along and told me I was wrong

 2008-11-02, 15:55 #5 Flatlander I quite division it     "Chris" Feb 2005 England 31×67 Posts Okay, I give up.
2008-11-17, 18:44   #6
m_f_h

Feb 2007

1101100002 Posts

Quote:
 Originally Posted by Prime95 I received this email today. The number is not prime, anyone have other ideas? 20120121122515626145776622735224615338815731191617
I inserted commas as to get numbers between 01 and 26, but in the resulting text I only saw "egg". Upon rot13, I see SMART and other stuff.
Code:
? [20,12,01,21,12,25,15,6,26,14,5,7,7,6,6,22,7,3,5,22,4,6,15,3,3,8,8,15,7,3,11,9,16,17]
? Strchr(Vecsmall(%+vector(#%,i,64)))
"TLAULYOFZNEGGFFVGCEVDFOCCHHOGCKIPQ"
/*pasted into rot13 */
GYNHYLBSMARTTSSITPRIQSBPPUUBTPXVCD
What's the probability of /accidentally/ getting "SMART", using two elementary/natural encoding methods (# of letter in the alphabet, and rot13) ?

PS: I used the "maximum munch principle" for putting the commas, but maybe military people are less scientific and some other splitting up was intended - I didn't check if something more reasonable can be obtained.
PPS: first I was intrigued by the repetition at the beginning and tried direct ascii conversion using maximum munch principle: 201,201,211,225,156,... but this gives nothing afaics ; b.t.w. it is improbable that the message starts with 2 repeated letters (unless it is to be read from right to left).

Last fiddled with by m_f_h on 2008-11-17 at 18:53

 2008-11-18, 12:22 #7 hhh     Jun 2005 37310 Posts The other question is: Do we really want to help officers in Iraq, commissioned or not, help doing their work? I would not, even if I was not too lazy to think about puzzles with no clue whatsoever. Oops, did I just annihilate my chance of ever getting a visa for the States? H.
2008-11-19, 03:56   #8
Orgasmic Troll
Cranksta Rap Ayatollah

Jul 2003

28116 Posts

Quote:
 Originally Posted by m_f_h [/code]What's the probability of /accidentally/ getting "SMART", using two elementary/natural encoding methods (# of letter in the alphabet, and rot13) ?
The chances of getting "SMART"? Infinitesimally small. The chances of getting a 5 letter English word?

29 different five letter sequences (incorrectly assuming independence), roughly 8600 5 letter words in the English language, the chances of NONE of the sequences containing a word is (1-8600/26^5)^29

...so about 1 out of 50.

(if you don't like my independence assumption, we can take the 7 different blocks of letters that don't interact for a lower bound. That gives us about 1 out of 200)

Last fiddled with by Orgasmic Troll on 2008-11-19 at 03:59

 2008-11-21, 16:10 #9 10metreh     Nov 2008 91216 Posts A possible clue: The first 11 digits are all 0, 1 or 2. Digit counts: 0 appears 2 times 1 appears 12 times 2 appears 10 times 3 appears 4 times 4 appears 2 times 5 appears 6 times 6 appears 6 times 7 appears 5 times 8 appears 2 times 9 appears 1 time There is a rather uneven distribution of digits, and most digits appear an even number of times. Of course all of this could be chance... Last fiddled with by 10metreh on 2008-11-21 at 16:21
 2008-11-21, 17:49 #10 uigrad     Aug 2008 2×43 Posts A) Since there are 50 digits, I spread them out in rows of 5: Code: A) B) C) 2 0 1 2 0 VA 2 0 1 2 0 1 2 1 1 2 NY 1 - - - - 2 5 1 5 6 WV 2 - - - - 2 6 1 4 5 WV 2 - - - - 7 7 6 6 2 TX 7 - - - - 2 7 3 5 2 NC 2 - - - - 2 4 6 1 5 VA 2 - - - - 3 3 8 8 1 FL 3 - - - - 5 7 3 1 1 SD 5 7 3 1 1 9 1 6 1 7 CA 9 1 6 1 7 B) Since five of the ten groups started with '2', I began to think of zip codes. (All the zip codes around Wash DC start with 2, so this stood out). So, I put the state letters beside each group of 5. C) I fed them into a zip code lookup function, forwards, backwords, down, and up, but only found 5 valid codes (out of 40): Forwards: 20120 ... ... Sully Station:Fairfax:VA 57311 ... ... Farmer:Hanson:SD 91617 ... ... Valley Village:Los Angeles:CA Backwords: nothing Down: 21227 ... ... Baltimore:Baltimore:MD Up: 95322 ... ... Santa Nella:Merced:CA Diagonals: nothing I found it really peculiar that the only digits that made valid zip codes were along the top, left, and bottom of my chart. I'm sure it's just coincidence though. I don't have any more zip code ideas. I'm posting here to possibly spur someone else on Last fiddled with by uigrad on 2008-11-21 at 17:55 Reason: typo
 2008-11-25, 22:33 #11 Ken_g6     Jan 2005 Caught in a sieve 5×79 Posts It's kind of odd that the number starts with a 2, then two entries of 012. I wonder if somebody left out some character code indicator, e.g.: 2 0x12 0x12 1122515626145776622735224615338815731191617 Now, 12 could be a form feed character; or it could be the size of something. Removed speculation that didn't add up... OK, I give up for now. Last fiddled with by Ken_g6 on 2008-11-25 at 22:38 Reason: Removed speculation that didn't add up...

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