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Old 2019-09-20, 11:53   #1
enzocreti
 
Mar 2018

17·31 Posts
Default Probability to find a probable prime

pg(215),pg(69660),pg(92020) and pg(541456) are prp...


215, 69660, 92020 and 541456 are 0 mod 43 and 10^m mod 41...


i am trying to find the next pg(43s) probable prime and I am considering the multiples of 43 which are congruent to 1 mod 41 as 69660...
a needle in the haystack do you think?


Any trick to accelerate the search?

Last fiddled with by enzocreti on 2019-09-20 at 11:56
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Old 2019-09-20, 13:43   #2
enzocreti
 
Mar 2018

20F16 Posts
Default candidate

A candidate is:


(2^2234624-1)*10^672689+2^2234623-1, no factor upto 10^7
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Old 2019-09-23, 06:13   #3
enzocreti
 
Mar 2018

17×31 Posts
Default THE NUMBER IS NOT PRP

Unfortunally the number is composite!
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