20040817, 15:02  #1 
6809 > 6502
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Aug 2003
101×103 Posts
2^{2}·7·389 Posts 
Latteral thinking puzzle
Complete this finite series.
5, 1 , 2, 5 , 7,... Spoilerise the important parts of your answers. 
20040820, 05:18  #2 
6809 > 6502
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Aug 2003
101×103 Posts
10892_{10} Posts 
No takers? I will reveal the next element in the series.

20040821, 23:19  #3 
6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
25214_{8} Posts 
Next element is : 3
again this is a finite series. This is a lateral thinking problem, so you can never solve it with math (although math can help). 
20040823, 13:16  #4 
6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
2^{2}×7×389 Posts 
There are 12 elements in this series.

20040824, 14:27  #5 
6809 > 6502
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Aug 2003
101×103 Posts
2A8C_{16} Posts 
Obviously nobody is interested......
So here is the answer: Numeric representation of the day of the week for the first day of the month for this year. 
20040901, 14:38  #6 
Mar 2004
381_{10} Posts 
I use a shifted version of that sequence to quickly calculate the day of the wee for any day.
1, 4, 4, 0, 2, 5, 0, 3, 6, 1, 4, 6 is easy to remember 144, 025, 036, 146 Add the number of the day in the month and also 2 for 2003, 4 for 2004, 5 for 2005, 6 for 2006, 0 for 2007 calculate the result mod 7, then convert 0 for saturday, 1 for sunday, 2 for monday... 
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