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#1 |
Mar 2018
22·7·19 Posts |
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which is the smallest even number N (in base 10) such that converted in base 2 contains five 1's?
I guess 94? Last fiddled with by enzocreti on 2019-11-06 at 15:20 |
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#2 |
6809 > 6502
"""""""""""""""""""
Aug 2003
101ร103 Posts
22·32·5·59 Posts |
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6210 is 1111102
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#3 |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
11001011011112 Posts |
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N = 2
210 = 1.1111.....2 |
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#4 |
"Curtis"
Feb 2005
Riverside, CA
14D716 Posts |
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#5 |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
17·383 Posts |
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#6 |
"Curtis"
Feb 2005
Riverside, CA
5×11×97 Posts |
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It also didn't say "at least 5 ones".
If I asked for a recipe using 3 eggs, and you gave me a recipe using infinite eggs, I wouldn't find you very helpful. |
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#7 |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
17×383 Posts |
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#8 |
"Composite as Heck"
Oct 2017
22·32·52 Posts |
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If we're going for pedantry points then you missed negative numbers. Pick a representation of negative numbers in binary, pick a fixed or variable word representation, pick how you define smallest. Naturally you'd think a<b for smallest, but the base 10 specification allows for an interpretation as the least number of digits when written in base 10.
-0 is 11111 in one's complement with a 5 bit word. It's the default winner of "least number of digits when written in base 10". |
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#9 | |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
17×383 Posts |
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![]() But a true pedant might interpret "smallest" to be numerical value. And if we are allowed to twist the definition boolean arithmetic with infinity: "-(โ AND (โ XOR 1))" has an infinity of 1's with the last digit as 0. Now we just need to define AND and XOR when dealing with infinities. |
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#10 |
Bamboozled!
"๐บ๐๐ท๐ท๐ญ"
May 2003
Down not across
32×5×11×23 Posts |
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Reminds me of the programmer who, before he went shopping, was told by his wife: "Buy a loaf of bread and, if they have any eggs, get a dozen." He came back with 12 loaves of bread and no eggs.
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#11 |
Feb 2017
Nowhere
22×1,459 Posts |
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