mersenneforum.org oʇᴉuᴉℲ oɔoᴉפ - ɹǝʌO ǝɯɐפ
 Register FAQ Search Today's Posts Mark Forums Read

 2020-11-05, 08:29 #1 Alberico Lepore     May 2017 ITALY 22×112 Posts oʇᴉuᴉℲ oɔoᴉפ - ɹǝʌO ǝɯɐפ civil disobedience or noncooperation Last fiddled with by Alberico Lepore on 2020-11-14 at 19:39
 2020-11-05, 09:17 #2 Batalov     "Serge" Mar 2008 Phi(4,2^7658614+1)/2 22·3·5·157 Posts Anyone can factor N=187! Try and factor something really hard, like N=6 or ...maybe 15.
2020-11-05, 10:04   #3
xilman
Bamboozled!

"𒉺𒌌𒇷𒆷𒀭"
May 2003
Down not across

2·72·109 Posts

Quote:
 Originally Posted by Batalov Anyone can factor N=187! Try and factor something really hard, like N=6 or ...maybe 15.
Actually if he had a working implementation of Shor's algorithm and used it to factor 15 I would be rather impressed.

2020-11-05, 13:18   #4
Dr Sardonicus

Feb 2017
Nowhere

7×647 Posts

Quote:
 Originally Posted by Batalov Anyone can factor N=187! Try and factor something really hard, like N=6 or ...maybe 15.
First time I read this I thought it said "N= 187!" -- the product of the integers from 1 to 187.

I can factor 187 mentally (2 doesn't divide it, 3 doesn't divide it, 5 doesn't divide it, 7 doesn't divide it, 11, -- divides it!) , and anyone can factor 187! with pencil and paper, if they can reckon the primes up to 187.

 2020-11-05, 13:22 #5 mathwiz   Mar 2019 9F16 Posts If it really is "game over", maybe Alberico will finally stop posting?
2020-11-05, 13:24   #6
retina
Undefined

"The unspeakable one"
Jun 2006
My evil lair

22·5·307 Posts

Quote:
 Originally Posted by Alberico Lepore red error correct is ...
Hmm. You take something that doesn't work, and then "fix" it with something else that doesn't work.

How are you coming along with the factors for the 18 digit challenge?

 2020-11-15, 17:56 #7 Batalov     "Serge" Mar 2008 Phi(4,2^7658614+1)/2 22·3·5·157 Posts