20151013, 08:27  #1 
Oct 2015
1_{8} Posts 
Official 'exchange of inanities' thread [Was: mm127 is prime, cuz I say so]
...(2^(2^(2^n1)1)1)...
I mean... isn't that at least a proof that there's an infinate amout of them? Try it with how meny primes you like... and with how meny 2^....1 you like... it always works 
20151013, 13:22  #2 
Romulan Interpreter
"name field"
Jun 2011
Thailand
23215_{8} Posts 
That is false. For n=4, all are composite. Also for n=11, all are composite.

20151013, 13:25  #3  
Nov 2003
2^{2}·5·373 Posts 
Quote:
every number in the sequence is prime. You have a strange notion about what constitutes a proof. Quote:
I suggest that you think about what you wrote. For example, please prove to us that 2^(2^1271)  1 is prime. Last fiddled with by R.D. Silverman on 20151013 at 13:28 

20151013, 13:26  #4 
Undefined
"The unspeakable one"
Jun 2006
My evil lair
2×3,167 Posts 

20151013, 13:32  #5  
"Forget I exist"
Jul 2009
Dumbassville
2^{6}·131 Posts 
Quote:
2) by that same logic m=2^n1 must be prime for 2^m1= 2^(2^n1)1 to have a chance at being prime. 3) as LaurV pointed out not all n that are prime will allow 2^n1 to be prime. 

20151013, 13:59  #6  
Nov 2003
2^{2}·5·373 Posts 
Quote:
However, I'd still like an answer to my question as to why the OP thinks that presenting a sequence of numbers is in any way a "proof". There were no mathematical statements asserting that some (set of) condition(s) is true, nor were there any logical statements. It was just a list of numbers. How can this be a proof? 

20151013, 14:03  #7 
Aug 2002
Buenos Aires, Argentina
1422_{10} Posts 

20151013, 14:14  #8  
Nov 2003
2^{2}·5·373 Posts 
Quote:
It is hard to correct someone's misconceptions without knowing how and why they believe what they believe. A simple statement that what was posted is not a proof says very little./// We need to know why the OP thought that simply presenting a sequence of numbers might be a proof. Last fiddled with by R.D. Silverman on 20151013 at 14:14 Reason: typo 

20151013, 14:24  #9  
"Forget I exist"
Jul 2009
Dumbassville
2^{6}·131 Posts 
Quote:


20151013, 14:25  #10 
Nov 2003
2^{2}·5·373 Posts 
Gibberish from someone who hasn't yet passed first year algebra.
Last fiddled with by R.D. Silverman on 20151013 at 14:26 
20151013, 14:29  #11 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}·131 Posts 

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