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Old 2006-12-13, 00:34   #56
Citrix
 
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Quote:
Originally Posted by geoff View Post
Is this post a description of the SPH algorithm?
Looks like the SPH algorithm.
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Old 2006-12-14, 03:29   #57
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Default new files and status

Code:
K 	Weight 	At 2^	Testing up to 2^	Reserved by
18534	92	1325000
23451	230	1601888      2000000            Jean Penne
60849	263     1406310      2000000            Jean Penne  
64494	93	1362818                         tcadigan
66741	0 	~~~~~~~~~BASE 4 SIERPINSKI NUMBER~~~~~~~~~	

Total Weight = 678
Average Weight= 169.5

Sieving Completed (Billions): 0-5500
geoff finished his range and found 31 new factors. attached files are each k's file with the numbers removed. thanks!

if interested the factors found were:
Code:
5005994642413 | 23451*2^1924232+1
5013026869583 | 23451*2^1924988+1
5017001339947 | 23451*2^1661624+1
5019761756783 | 60849*2^1706094+1
5029175730743 | 60849*2^1419090+1
5042363284489 | 60849*2^1385166+1
5057071611461 | 60849*2^1854066+1
5084683863607 | 18534*2^1799454+1
5110582644113 | 23451*2^1788944+1
5123126337383 | 60849*2^1879590+1
5132064179287 | 18534*2^1993014+1
5132383706077 | 60849*2^1442706+1
5138529248959 | 60849*2^1649886+1
5159363407993 | 23451*2^1896992+1
5204363940289 | 23451*2^1836784+1
5213462298949 | 64494*2^1852658+1
5239864808359 | 60849*2^1870674+1
5267254635953 | 23451*2^1618844+1
5278057962883 | 64494*2^1576346+1
5288032742747 | 60849*2^1688310+1
5309811652417 | 60849*2^1414410+1
5314758535139 | 60849*2^1606926+1
5387876951543 | 64494*2^1707554+1
5388081137773 | 23451*2^1976912+1
5407646427083 | 23451*2^1654772+1
5432400900539 | 64494*2^1428266+1
5434314816137 | 60849*2^1481754+1
5483115369931 | 60849*2^1766574+1
5487123017581 | 60849*2^1765746+1
5493702516077 | 60849*2^1598586+1
5499608142031 | 64494*2^1849322+1
Attached Files
File Type: zip new_results.zip (29.9 KB, 104 views)

Last fiddled with by tcadigan on 2006-12-14 at 03:32
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Old 2007-01-01, 20:25   #58
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Code:
K 	Weight 	At 2^	Testing up to 2^	Reserved by
18534	92	1325000                              Citrix
23451	230	1601888      2000000            Jean Penne
60849	263     1406310      2000000            Jean Penne  
64494	93	1362818                              tcadigan
66741	0 	~~~~~~~~~BASE 4 SIERPINSKI NUMBER~~~~~~~~~	

Total Weight = 678
Average Weight= 169.5

Sieving Completed (Billions): 0-5500

Reserving 18534!

Last fiddled with by Citrix on 2007-01-01 at 20:26
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Old 2007-01-08, 06:47   #59
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Reserving 5500-7500 for sieving.
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Old 2007-01-23, 20:33   #60
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18534 is at 1.5M no primes, continuing. Geoff, you might want to update the sieve file for some extra boost.
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Old 2007-01-31, 08:03   #61
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Code:
K 	Weight 	At 2^	Testing up to 2^	Reserved by
18534	92	1500000                         Citrix
23451	230	1601888      2000000            Jean Penne
60849	263     1406310      2000000            Jean Penne  
64494	93	1362818                         tcadigan
66741	0 	~~~~~~~~~BASE 4 SIERPINSKI NUMBER~~~~~~~~~	

Total Weight = 678
Average Weight= 169.5

Sieving Completed (Billions): 0-7500
Geoff has completed his range and sends "I got about 415 kp/s on a P2/400 with sr2sieve 1.4.18 for this range."

the resulting files are attached
Attached Files
File Type: zip S_4.zip (58.8 KB, 109 views)

Last fiddled with by Citrix on 2007-01-31 at 08:18
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Old 2007-01-31, 21:44   #62
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Can you give me some instructions on how to use sr2sieve and the sieve file for sierpinski base 4?
Then I could do some more sieving.
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Old 2007-02-01, 15:22   #63
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Default How did you compute the weights?

I am wondering at the method you were using to compute the weights of the remaining four candidates...
While using the psieve 3.21 program written by Chris Nash and Paul Jobling :

psieve -q -e -b4 <k value>, I found :

23451 : 460
60849 : 526

so, exactly two times yours!
And the program refuses to compute the weights for 18534 and 64494 because these k values are even...
I am very interested to know about that, because I wish now to estimate the chance we have to prove the base 4 Sierpinski conjecture, using the method suggested by Yves Gallot in his paper :

"On the number of primes in a sequence"

For now, I computed all the "frequencies" as defined by Ray Ballinger and Wilfrid Keller, up to f19, and registered all of the 22242 corresponding Keller primes (k, n) pairs, so, our work can now be precisely described.

(I will communicate these results soon)

I can assert the four remaining candidates belong at least to f20, but it remains to evaluate the chance we have to eliminate all of them in a not too far future!

Thank you by advance and Best regards,
Jean
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Old 2007-02-01, 23:04   #64
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Quote:
Originally Posted by Mystwalker View Post
Can you give me some instructions on how to use sr2sieve and the sieve file for sierpinski base 4?
Then I could do some more sieving.
Download sr2sieve from http://www.geocities.com/g_w_reynolds/sr2sieve/. For example: To sieve from 5500 to 7500 billion, create a new directory containing a copy of SoB.dat (case-sensitive name), and a text file sr2work.txt containing the line "5500,7500" (without quotes). Then run `sr2sieve -s'. You can stop with ctrl-c and it will resume from where it left off when restarted. The factors will be recorded in factors5500.txt.

Last fiddled with by geoff on 2007-02-01 at 23:08 Reason: fix url
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Old 2007-02-03, 00:14   #65
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Quote:
Originally Posted by Jean Penné View Post
I am wondering at the method you were using to compute the weights of the remaining four candidates...
While using the psieve 3.21 program written by Chris Nash and Paul Jobling :

psieve -q -e -b4 <k value>, I found :

23451 : 460
60849 : 526

so, exactly two times yours!
And the program refuses to compute the weights for 18534 and 64494 because these k values are even...
I am very interested to know about that, because I wish now to estimate the chance we have to prove the base 4 Sierpinski conjecture, using the method suggested by Yves Gallot in his paper :

"On the number of primes in a sequence"

For now, I computed all the "frequencies" as defined by Ray Ballinger and Wilfrid Keller, up to f19, and registered all of the 22242 corresponding Keller primes (k, n) pairs, so, our work can now be precisely described.

(I will communicate these results soon)

I can assert the four remaining candidates belong at least to f20, but it remains to evaluate the chance we have to eliminate all of them in a not too far future!

Thank you by advance and Best regards,
Jean


I can't remember for sure. I did use psieve. The weights are base 2. So the actual base 4 weights will be twice this.

For the even k's, you calculate this

weight of k/2 in base 2 and base 4. Divide weight in base 4 by 2 and subtract from weight in base 2. TO get actual weight. THen can multiply by 2 to get weight of k in base 4.

What is the status of your k's, so we can update the sieve file.

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Old 2007-02-03, 04:30   #66
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Quote:
Originally Posted by geoff View Post
Download sr2sieve from http://www.geocities.com/g_w_reynolds/sr2sieve/. For example: To sieve from 5500 to 7500 billion, create a new directory containing a copy of SoB.dat (case-sensitive name), and a text file sr2work.txt containing the line "5500,7500" (without quotes). Then run `sr2sieve -s'. You can stop with ctrl-c and it will resume from where it left off when restarted. The factors will be recorded in factors5500.txt.
Mystwalker...so...just stating the obvious...you'd get the dat for the most recent zip posted...rename it to SoB.dat and then follow the rest of geoff's instructions.

whenever you're done make the results available, I seem to have taken up that since there isn't a whole lot of movement in the project and it's just as easy for me to do it as anyone else
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