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#12 |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
10,753 Posts |
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#13 | |
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Nov 2003
22×5×373 Posts |
Quote:
All of these numbers are being done with SNFS. There are currently 8 left. One has been sieved (3,2,391-) and one is being sieved (3,2,367-). |
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#14 | |
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Nov 2003
22·5·373 Posts |
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I have finished sieving both 6,281- and 5,329-. The LA failed on my first attempt for 6,281-. I ran some memory diags which turned up nothing and am trying again. It should finish in 4 days. 5,329- is filtered and waiting for 6,281- to finish before I do the LA. These will be my last two Cunningham numbers for a while. I no longer have access to sufficient resources. |
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#15 | |
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Jun 2003
The Texas Hill Country
32·112 Posts |
Quote:
Given the slow progress of my LA resources, I also decided to do a bit more sieving on the (sieving) "completed" projects in the hopes of reducing the matrix size, and thus the time required to solve them. The LA for 5,311+ is right on schedule. I have completed 4695107 of the 4727789 iterations and expect it to finish later today. We have selected 10,229+ for the "next" project and the extremely limited survey sieving that I have completed confirms Paul's estimates of required sieving. In an effort to try to harness additional computers, I have done some experimentation with a scheme to get the siever to run in a Condor environment. This may also lead to the ability to reintroduce "off line" participation. However, unless someone wants to do a lot of hand-holding, we are not there yet. |
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#16 | |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
250018 Posts |
Quote:
Paul |
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#17 | |
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Nov 2003
22×5×373 Posts |
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send the data via CD. It depends whether I can scrounge up a different machine. |
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#18 |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
1075310 Posts |
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#19 |
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Jun 2003
The Texas Hill Country
32×112 Posts |
End of processing for dependency 3.
Factorization completed after 6882.37 seconds, at Thu Nov 30 17:53:56 2006 Original number had 159 digits: 150650548844352814472034553603725365278060147080078718886994332064798998676174032863553350168785846893529217000119086372273707058271765344885514708578781094447 Probable prime factor 1 has 74 digits: 13132762900451821968706840158108829466847315743095478589617724372773046827 Probable prime factor 2 has 86 digits: 11471352219354375576867856155746425346416263800209213701608739475620813560935030594061 |
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#20 |
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Nov 2003
22·5·373 Posts |
The LA ran OK this time.
We have an interesting phenomenon: TWO ECM near misses on the same number. 6,281- split unexpectantly into 3 factors. 6,281- C162 = p50.p53.p61 p50 = 11762786832623811560644277958387970995125858157407 p53 = 28717354535597728468537227064151476862005971007351781 p61 = 1543716606774880990775734941009568252713968653903070066195497 The LA for 5,329- is now in progress. |
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#21 | |
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Jun 2005
lehigh.edu
210 Posts |
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that as nearly two full ecm misses. The only slight quibble is that t50 = finding a known p50 to prob 62% [at which point, optimal computing use is to switch for looking for p55s]. That still leaves a 38% chance that a known/expected p50 SHOULD be left, and even 2*t50 leaves the prob at 1-1/(e^2) = .86466 (oops, 1/e gives 63.21%, not 62%), so still 13.5% of a p50 being left. So if a pool of 100 numbers starts with 8 p50's, say all with p45's and smaller removed, and we've found seven of them, the last one ought to be left for finding by snfs so long as there are other pools of near-term sieving candidates that haven't gotten t50 tests. As I've been saying elsewhere, I'd be happy to have a pool of the 31st to 131st easiest snfs numbers to run a 2nd t50 on (the 1st to 30th presumably being easy enough to run to leave that last 1/8 p50, if I recall Bob's earlier comment correctly). -Bruce |
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#22 |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
10,753 Posts |
The linear algebra is now well past the 50% mark. I hope to have factors some time next week, probably Monday or Tuesday.
Paul |
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