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#1 |
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Feb 2006
3 Posts |
Hi,
I have a question concerning the effectiveness of Pollard's p-1 method. For which size of prime factors (number of diggits) would one use this method? Thx R. |
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#2 | |
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"Bob Silverman"
Nov 2003
North of Boston
166158 Posts |
Quote:
any particular sized factor. Generally, one tries trial division first (to say log^2 N), followed by Pollard Rho, followed by P-1/P+1. One hopes to simply get lucky with P-1 before starting ECM. Running P-1 is equivalent to running ECM with just a SINGLE curve. P-1 runs a lot faster than ECM, which is why it is worthwhile. P-1 can, if you are lucky, rip out a 30 digit factor in a matter of seconds. It can also take a long time to find (say) a 15 digit factor. P-1 is especially effective for Cunningham numbers where one knows that the factor lies in a given equivalence class. |
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#3 |
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Feb 2006
3 Posts |
Ok, thanks a lot. Is there nothing to say about the size of the prime factor p if (p-1) is smooth and so the P-1 method is succesful?
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#4 | |
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"Bob Silverman"
Nov 2003
North of Boston
5·17·89 Posts |
Quote:
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#5 | |
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Bamboozled!
"๐บ๐๐ท๐ท๐ญ"
May 2003
Down not across
2×17×347 Posts |
Quote:
One can certainly say something about the probability, as a function of smoothness bound B, that a prime p of a given size in bits has p-1 which is B-smooth. As Bob says, running p-1 is essentially the same as running a singe ECM curve (if we don't know anything about the structure of possible divisors; the modification is straightforward if structure is known). Tables of success probabilities for ECM curves for particular bounds are easy enough to find. Paul |
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#6 | |
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"Bob Silverman"
Nov 2003
North of Boston
5×17×89 Posts |
Quote:
It simply said "smooth". Even with a specified bound, we can't say anything about the size; all we can do is give a probability distribution for the probability of finding factors of different sizes. And this does not really answer the question that I think was intended. |
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#7 |
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"Richard B. Woods"
Aug 2002
Wisconsin USA
22×3×641 Posts |
Robertcop,
Perhaps an explanation I wrote about P-1 a while back may be helpful: http://www.mersenneforum.org/showpos...89&postcount=3 Another way to put it is that trial factoring proceeds in order of increasing size of the factor one seeks, but P-1 proceeds in order of increasing size of the largest prime factor of [(the factor one seeks)-1]. There's a correlation between the order in which P-1 proceeds and the average size of the factor it finds, but it's not direct as it is with trial factoring. Last fiddled with by cheesehead on 2006-04-22 at 20:03 |
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#8 | |
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"Bob Silverman"
Nov 2003
North of Boston
5·17·89 Posts |
Quote:
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#9 | |
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"Nancy"
Aug 2002
Alexandria
1001101000112 Posts |
Quote:
Alex |
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#10 | |
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Bamboozled!
"๐บ๐๐ท๐ท๐ญ"
May 2003
Down not across
2×17×347 Posts |
Quote:
Bob, am I right? Paul |
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#11 | |
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"Richard B. Woods"
Aug 2002
Wisconsin USA
22×3×641 Posts |
Quote:
B) Suppose, OTOH, that Silverman correctly understood that my posting directed to "Robertcop" was directed to the OP -- I have the same question: what did he consider hypocritical? In case Silverman doesn't answer me here, can anyone else propose an explanation? I'm genuinely puzzled. I can conceive that Silverman could consider "Robertcop" to be negative in some way when directed to himself, but I can't think of a plausible reason for his specific response "Hypocrite" rather than something else. Inquiring llamas want to know. :) Last fiddled with by cheesehead on 2006-04-30 at 22:28 |
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