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#56 |
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"Nancy"
Aug 2002
Alexandria
2,467 Posts |
Sorry, no... had an exam yesterday and will have another (the last one!) on the 21st. I'll play with sqrt again after that.
Alex |
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#57 |
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"Nancy"
Aug 2002
Alexandria
2,467 Posts |
Turns out all I had to do was change a #define...
Code:
Original number had 244 digits: 2180075438084173168593947502718622130302257527967068979673625647025361320317722693777938884468406733797422512728450828995171625828330838682415089213199694141322162661316080591217910460859207203227286693244038606742662977922009304165840148925781 Probable prime factor 1 has 108 digits: 465248728728895394653153888943818531375975270853944206732179708325578302943996260672261958710669770611963071 Probable prime factor 2 has 136 digits: 4685827823840272482505664867616517656515469121675968181975198207240785431020525292215919392072745559212525121242512397104031773498892011 Well, that was it! ![]() Alex |
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#58 |
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Jul 2004
Potsdam, Germany
3·277 Posts |
Excellent work, Alex!
And clearly not an ECM miss.
Last fiddled with by Mystwalker on 2006-04-10 at 08:02 |
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#59 | |
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Nov 2003
164448 Posts |
Quote:
Nice result......
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#60 |
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May 2005
22×3×5 Posts |
Dear Alex,
May I ask you, is 5,349- is OddPerfectSearch's only roadblock left to prove any opn > 10^500 ? What a great pleasure it is to see your final result on the 5^349-1. Congratulations. Cheers, Joseph E.Z. Chein |
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#61 |
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"Phil"
Sep 2002
Tracktown, U.S.A.
100010111112 Posts |
Congratulations, Alex, on the completion of an impressive factorization! I see that this is the second-largest penultimate factor found of a Cunningham number.
To answer Joseph Chein's question, William has said that he believes that this was the last remaining roadblock, but that actually putting all this together in a proof will be necessary to verify it. The methods of the first Brent and Cohen paper should now be sufficient to show that any OPN > 10^500, but the methods of the second paper (with te Riele) should be able to push this limit somewhat higher, perhaps 10^625, or even greater. I don't know even if anyone has yet established that 2520(2521-1) and 2606(2607-1) at 314 and 366 decimal digits, respectively, are in fact the 13th and 14th perfect numbers in order of size. The next perfect number, 21278(21279-1) at 770 digits, presumably 15th, may actually be proven so given a few more roadblock SNFS factorizations. But the next one, 22202(22203-1) at 1327 digits, definitely seems out of reach without new methods, as it would require SNFS factorizations of numbers with over 400 digits. |
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#62 |
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May 2005
22×3×5 Posts |
Dear Philmoore,
Thanks. I guess you mean that William and his company might use BCR’s “lifting” algorithms to pushing opn > 10^625 or higher ?. Regards Joseph E.Z. Chein |
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#63 |
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"Nancy"
Aug 2002
Alexandria
2,467 Posts |
Thanks, Dennis, Bob, Joseph and Phil!
Alex |
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#64 | |
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"Phil"
Sep 2002
Tracktown, U.S.A.
3×373 Posts |
Quote:
http://wwwmaths.anu.edu.au/~brent/pub/pub116.html |
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#65 | |
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"William"
May 2003
New Haven
44768 Posts |
Quote:
All of this premature because I continue to work very long hours so that we don't even have to the tools to complete an "unstretched" proof, so it's early to squabble about whether now is the time to stretch the proof. |
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#66 | |
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Nov 2003
11101001001002 Posts |
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OK. Suppose those undertaking this project succeed in raising the bound. I have no doubt that they will succeed. Allow me to ask: What insight is gained by this computation? Allow me to quote Hamming: The purpose of computing is insight, not numbers. If this computation leads to any new mathematical insights about the problem, I will applaud it heartily. Until then, it is just mindless computing. On the other hand, if raising the bound helps convince people of the unlikelihood that OPN's exist, and thereby dissuades such people from trying to actually find an OPN, then I will also applaud the effort. |
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