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#12 |
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Feb 2004
France
22·229 Posts |
Numbers,
If you are interested in the LLT and its history, you should read the books of Paulo Ribenboim (A little book for bigger primes) and of HC. Williams (Edouard Lucas and Primality Testing). They provide many very interesting information about the Maths behind the LLT. Regards, Tony |
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#13 | ||
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"Richard B. Woods"
Aug 2002
Wisconsin USA
11110000011002 Posts |
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Quote:
Restated: Let NDD_30000000 be the number of decimal digits in S_30000000. Then there are over 9 million decimal digits in the value of NDD_30000000. You're both right. |
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#14 | |
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Jun 2003
2×7×113 Posts |
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Yes there is, you need 2 things 1) An understanding of FFT (Extremely complicated to explain; actually a modification of FFT) 2) Lots and lots of memory to store the decimal digits. Citrix |
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#15 | |
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"Richard B. Woods"
Aug 2002
Wisconsin USA
769210 Posts |
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The FFT is simply a tool used to speed up the calculations, not something essential to the Lucas algorithm. (You'll notice that Lucas never mentions FFT in his explanation.) Last fiddled with by cheesehead on 2005-09-07 at 04:09 |
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#16 | |
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Jun 2003
158210 Posts |
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What I am saying is that LL3154 etc can be generated without generating LL1,LL2 ... LL3154 using a modification of FFT. Though the complexity would be the same as 3154 multiplications. |
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#17 |
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"Phil"
Sep 2002
Tracktown, U.S.A.
21378 Posts |
There was an earlier thread that requested a proof of Lehmer's theorem that the Lucas-Lehmer test is a necessary and sufficient condition for the primality of 2^p-1 without using group theory. I have tried to distill the essence of the papers by Rosen and Bruce in The American Mathematical Monthly and have posted a proof on the Mersenne-wiki at:
http://www.mersennewiki.org/index.php/Lucas-Lehmer_Test Unfortunately, although the proof seems to be one of the simplest around in terms of required background in number theory, it does not give one the insight that a proof using more advanced abstract algebra gives. As usual in mathematics, abstraction often enables one to distinguish between characteristics of a particular problem and more general principles with wider applicability. Still, it is a nice proof, and the sufficiency requires almost no background at all, while the necessity requires application of quadratic reciprocity. Feel free to edit it if you can come up with improvements. Last fiddled with by philmoore on 2005-09-19 at 18:38 |
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#18 | |
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Jun 2005
Near Beetlegeuse
38810 Posts |
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#19 |
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Feb 2006
28 Posts |
Can anyone provide a simple (nothing much above first year calculus level) way to explain the proof of the LL theorem? I understand the theorem easily, but I don't fully understand the whole proof.
edit: I'd appreciate it if you could also give a relatively simple explaination of FFTs. Last fiddled with by Run800 on 2006-02-09 at 05:19 |
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#20 | |
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Nov 2003
22×5×373 Posts |
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The mathematics involved in the proof involves nothing more than simple theorems in elementary group theory and number theory, plus a little knowledge of finite fields. This body of knowledge does not lie "above" calculus. Indeed, it requires no knowledge of calculus at all. However, it does involve *elementary* mathematics that is not usually seen before college. So let me ask: How much number theory and group theory do you know? How much algebra do you know? Calculus is irrelevant. I can give a very short proof (less than 10 lines), but it requires knowing Lagrange's Theorem, and some stuff about multiplicative sub-groups of a finite field. The mathematics involved isn't more "advanced" than 1st year calculus. It is merely different. |
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#21 | |
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Nov 2005
608 Posts |
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As Bob said, there is a simple explanation, but it involves some abstract algebra that you might not know. It is possible to prove the LL test directly by simpler means, but it involves some messy and non-obvious modular arithmetic. This is likely the dilemma you are facing. John |
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#22 |
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Aug 2002
Buenos Aires, Argentina
101010101102 Posts |
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