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#199 | |
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May 2004
1C16 Posts |
Quote:
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#200 |
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Oct 2005
Italy
15316 Posts |
Ok but it is a correct prevision...
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#201 |
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"Robert Gerbicz"
Oct 2005
Hungary
2·743 Posts |
I also reveal my encryption: 44243291
that is 30402457=4424^2+3291^2 |
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#202 |
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Feb 2004
France
22×229 Posts |
Congratulations to the GIMPS !!
Welcome M43 ! What a nice present for Christmas ! Tony |
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#203 | |
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Sep 2002
Vienna, Austria
21910 Posts |
Use the classical "n+13" method on GUVEGLZVYYVBASBHEUHAQERQNAQGJBGUBHFNAQSBHEUHAQERQNAQSVSGLFRIRA yields thirtymillionfourhundredandtwothousandfourhundredandfiftyseven
Another one: 809509975=0x30402457........ Quote:
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#205 |
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Dec 2005
48 Posts |
I'll reveal my encryption.
My encrypted guess was 0x36C9248137FFFE I wrote a C++ program with the psuedo code from this post http://www.mersenneforum.org/showthread.php?t=1508 if you calculate the false residue of 30402457 written backwards as 75420403 you get this false residue 0x36C9248137FFFE Regards, Michael Eaton Last fiddled with by F960897 on 2005-12-24 at 19:08 |
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#206 |
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Oct 2005
Italy
3·113 Posts |
I wrote a small Java program to compute the fake residue.
you can download here: http://pacionet.zapto.org/privato/fake.zip The file is password protected and the password is the exponent of the prime just discovered. To compile: javac fake.java To run: java fake 12345678 where '12345678' is the decimal form of the exponent. Of course you must have a JVM installed to run it. MERRY CHRISTMAS MERSENNE FORUM |
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#207 |
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"Nancy"
Aug 2002
Alexandria
9A316 Posts |
Mine was prime_pi(30402457) = 1881339 = 0x1CB4FB
Alex |
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#208 | |
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Oct 2005
Italy
33910 Posts |
Quote:
It seems really too far in the photo .... http://www.noao.edu/outreach/aop/observers/m44.html |
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#209 |
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Oct 2003
Croatia
23·3·19 Posts |
Congratulations!!!
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