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Old 2021-05-09, 09:14   #1
Alberico Lepore
 
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Default Lepore Factorization nr.88

I've tried again

Lepore Factorization nr.88

https://www.academia.edu/48848013/Le...rization_nr_88
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Old 2021-05-11, 17:36   #2
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free copy



@CRGreathouse your number
https://mersenneforum.org/showthread.php?t=25929


390644893234047643

sqrt(390644893234047643/2)=441692991 -> 441692991 ; 441692989 ;441692987 ; 441692985
sqrt(390644893234047643) =625015914 -> 625015913 ; 625015911 ;625015909 ; 625015907


(390644893234047643-3)/8-Q-[4-(441692985-7)*(441692985-5)/8]=441692985*X

(390644893234047643-3)/8-P-[4-(625015907-7)*(625015907-5)/8]=625015907*X

Q=441692985*x+152029391

P=625015907*y+60099037

p*(q-625015907)/8=625015907*y+60099037 ,p*q=390644893234047643

p=625015921-8*y

q*(p-441692985)/8=441692985*x+152029391,p*q=390644893234047643

q=884426299- 8*x





Use LLL alghorithm to find one solution of

m*(a1)*(a3)+n*(b1)*(b3) = N*t +T

m*(a1)*(a4)-n*(b1)*(b4) = N*s + S

m*(a2)*(a3)-n*(b2)*(b3) = N*w + W

64 < T <= 64 *j where j is integer > 1

0<S <= sqrt(N)

0<W <= sqrt(N)

a1=441692985 , a2=152029391 ,a3=625015907 ,a4=60099037

b1=8 , b2=884426299 , b3=8 , b4=625015921
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Last fiddled with by Alberico Lepore on 2021-05-18 at 10:27
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Old 2021-07-10, 14:22   #3
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Quote:
Originally Posted by Alberico Lepore View Post
I've tried again

Lepore Factorization nr.88

https://www.academia.edu/48848013/Le...rization_nr_88
How to bypass the difficulty of factoring an RSA number

I've tried again

Lepore Factorization nr.88
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Old 2021-07-13, 14:43   #4
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Quote:
Originally Posted by Alberico Lepore View Post
I've tried again

Lepore Factorization nr.88

https://www.academia.edu/48848013/Le...rization_nr_88
I've tried again

Lepore Factorization nr.88

another photo for my net-friends
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