Team sieve for Kosta C198 - Page 4

EdH · 2020-05-08, 14:44

Quote:

Originally Posted by VBCurtis

. . .
I saw errors most often on #40 and #53. I saw 53 today, so I bet you caught that one today too.

I'm not seeing any more short time errors. If you note any more of any length, let me know next time you post. Thanks!

VBCurtis · 2020-05-11, 01:59

Ed-
I saw no more errors.

All-
We've reached Q=80M, so we're done! I'll cat and remdups these presently, and will post the number of unique relations we achieved as an edit to this post shortly.

Thanks for your help, everyone!

Stats: 137.4M unique relations, 59.6M duplicates. That's 197M total relations from Q=2-80M. Lots of these will duplicate the nfs@home run, but we'll still save a bunch of inefficient high-Q effort!

swellman · 2020-05-11, 12:39

Quote:

Originally Posted by VBCurtis

Ed-
I saw no more errors.

All-
We've reached Q=80M, so we're done! I'll cat and remdups these presently, and will post the number of unique relations we achieved as an edit to this post shortly.

Thanks for your help, everyone!

Stats: 137.4M unique relations, 59.6M duplicates. That's 197M total relations from Q=2-80M. Lots of these will duplicate the nfs@home run, but we'll still save a bunch of inefficient high-Q effort!

Nice. I’ll keep an eye on NFS@Home job for this composite, though it probably won’t finish sieving until midsummer. But ~100M relations added onto what 15e generates should get this onto LA.

I wonder if a C200 is possible on 15e using this approach? Question for another day.

VBCurtis · 2020-05-11, 14:39

Quote:

Originally Posted by swellman

I wonder if a C200 is possible on 15e using this approach? Question for another day.

There's no doubt this approach makes C200-201 reasonable with 15e. If yield looks sketchy, we simply run Q=20-100M on I=16 rather than the A=30 that we chose for this job. We'd get 30% more relations -> 220M uniques before starting nfs@home. Or, if it proves faster, Q=20-150M on A=30 and then nfs@home.

swellman · 2020-06-07, 19:46

Mike has withdrawn his reservation for postprocessing this job. Anybody interested in taking it on? I have a couple of i7s each with 32 Gb of memory but it would take months to finish this job on either rig.

VBCurtis · 2020-06-07, 21:03

Sure, I can do it; I already have the CADO'ed relations anyway.
You can post the reservation for me.

2020-05-11, 01:59	#35
VBCurtis "Curtis" Feb 2005 Riverside, CA 1001011111101₂ Posts	Ed- I saw no more errors. All- We've reached Q=80M, so we're done! I'll cat and remdups these presently, and will post the number of unique relations we achieved as an edit to this post shortly. Thanks for your help, everyone! Stats: 137.4M unique relations, 59.6M duplicates. That's 197M total relations from Q=2-80M. Lots of these will duplicate the nfs@home run, but we'll still save a bunch of inefficient high-Q effort! Last fiddled with by VBCurtis on 2020-05-11 at 02:36

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2020-06-07, 19:46	#38
swellman Jun 2012 5774₈ Posts	Mike has withdrawn his reservation for postprocessing this job. Anybody interested in taking it on? I have a couple of i7s each with 32 Gb of memory but it would take months to finish this job on either rig.

2020-06-07, 21:03	#39
VBCurtis "Curtis" Feb 2005 Riverside, CA 12FD₁₆ Posts	Sure, I can do it; I already have the CADO'ed relations anyway. You can post the reservation for me.