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Old 2019-07-02, 02:28   #12
axn
 
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Quote:
Originally Posted by a1call View Post
But at least you didn't have to use your programming skills this time.
Ah, but you see, I did have to use it
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Old 2019-07-02, 03:03   #13
a1call
 
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Good, my data mining worked.
Thanks.
I will still try it the old fashioned way for now. Getting too old for programming.
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Old 2019-07-02, 07:29   #14
LaurV
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This is not really a puzzle, it is more like a prank.

That huge "size 40" tricked me a little, until I realized that for 14 moves to be a cycle you can move maximum 7 steps in one direction, as you will need 7 steps to come back. Therefore, jumping two squares every time, there is no way to reach the other end of a "size 40" board (the standard chess board is "size 8", not "size 64", grrr). Then it clicked to me they mean area, or the number of squares, and in this case you can't have a board too large. A 6x7 board will be already larger, so you must stay in 5x8, or 6x6, or you still can play with a 10x4. The Nx3 would be too narrow, I mean, the only way you can make a non-intersecting track with length 14 is on a 14x3 board, and that is already "size 42", isn't it??? And then "bang!" it hit me! haha.

It took me like 10 minutes.

Edit: pencil and paper, no code, no calculator for area. (Long Live Mathologer, one of his videos shows how to calculate area of tilted rhombuses, by wrapping them in imaginary non-tilted square boxes and subtract the surrounding area).

Last fiddled with by LaurV on 2019-07-02 at 08:33
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Old 2019-07-02, 08:03   #15
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Quote:
Originally Posted by LaurV View Post
Long Live Mathlogger
Mathologer?
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Old 2019-07-02, 08:35   #16
LaurV
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Quote:
Originally Posted by axn View Post
Mathologer?
Grr.. fixed, and sorry for this stupid typing mistake - one of the things I hate most is making fun of people's names...
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Old 2019-07-05, 13:06   #17
Dieter
 
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Am I right with the following summing up:

Each vertex is belonging to two edges (and not more!).

It is forbidden that 3 consecutive points lie in a straight line, because :

„Two edges meeting at a corner are usually required to form an angle that is not straight (180°); otherwise, the collinear line segments will be considered parts of a single side.“
(Wiki, simple polygon)
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Old 2019-07-05, 18:38   #18
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I don't believe the intent was to forbid two consecutive jumps in the same direction.


You could interpret it as saying that the geometric shape surrounded by the path must be a simple polygon. Said simple polygon might have fewer vertices than there are jumps in the path, if consecutive jumps are in the same direction.
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Old 2019-07-12, 15:11   #19
Dieter
 
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Quote:
Originally Posted by uau View Post
I don't believe the intent was to forbid two consecutive jumps in the same direction.


You could interpret it as saying that the geometric shape surrounded by the path must be a simple polygon. Said simple polygon might have fewer vertices than there are jumps in the path, if consecutive jumps are in the same direction.
Probably you are right. Fortunately it doesn‘t matter - there is at least one solution without these problems.
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Old 2019-07-21, 12:06   #20
yae9911
 
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Nothing was said about the side lengths of the path polygon, so any number of consecutive moves in the same direction is allowed.
"board of size mXn" was chosen instead of "board of area ...." to avoid interference with the enclosed area of the knight's path.
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Old 2019-07-25, 00:04   #21
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for those who have found the solution.
and who is bored like me. try to find instead of a difference in area 7.
the product of both areas 195.
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Old 2019-07-25, 09:57   #22
Dieter
 
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Quote:
Originally Posted by Kebbaj View Post
for those who have found the solution.
and who is bored like me. try to find instead of a difference in area 7.
the product of both areas 195.
195=3*5*13, so the only realistic possibility is 13*15

It‘s no problem to find shapes with area 13 respectively 15.
Or I have misunderstood your problem...
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