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#1 |
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Mar 2018
2·5·53 Posts |
Pg numbers are numbers of the form
(2^k-1)*10^d+2^(k-1)-1 where d is the number of decimal digits of 2^(k-1)-1 pg(215), pg(51456), pg(69660), pg(92020) and pg(541456) are probable primes where k is congruent to 10^m mod 41, for m some nonnegative integer. 215 for example is 10 mod 41. now when k is congruent to 10^m mod 41 and pg(k) is probable prime, then 10*pg(k) is congruent to 10^s mod 37 or mod 307 where s is a nonnegative integer 215*10 is 1 mod 307 51456*10 is 1 mod 37 69660*10 is 1 mod 37 92020*10 is 10 mod 37 541456*10 is 1 mod 307 37 and 307 are primes with the same first and last digit (3 and 7) so it seems that if pg(k) is prime and k is 10^m mod 41, then: or pg(k) is 10^s mod 37 (cases 51456, 69660, 92020) or if pg(k) is not 10^s mod 37 then 10*pg(k) is 10^s mod 307 (cases 215 and 541456) Last fiddled with by enzocreti on 2019-07-15 at 14:37 |
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