M51 arithmetic - Page 5

uau · 2019-01-11, 20:03

Quote:

Originally Posted by bsquared

Do you have a program that exhaustively searches for these or did you do some sort of proof?

A short Python script that generates all the possible numbers from given digits. I'm not sure whether I should post it here. Using the script obviously makes it pretty pointless to generate numbers by hand. On the other hand you could compare things like "which digits generate most consecutive numbers from 0" - for example 31415926 fails at 607 already.

Batalov · 2019-01-12, 00:29

Killjoy :-)

I was lazily thinking about running the same-ish script and then I thought that people will say "Killjoy!" so I didn't.

LaurV · 2019-01-12, 02:30

Quote:

Originally Posted by uau

A short Python script that generates all the possible numbers from given digits. I'm not sure whether I should post it here. Using the script obviously makes it pretty pointless to generate numbers by hand.

Exactly, fun is gone. Please don't.

petrw1 · 2019-01-12, 03:16

90 = 8 * 2 * 5 + 9 + 9 / 3 / 3

LaurV · 2019-01-12, 05:57

Quote:

Originally Posted by petrw1

90 = 8 * 2 * 5 + 9 + 9 / 3 / 3

you missed an 8
In fact, the 2*5 combination is quite welcomed to make tens, hehe
90 = 8*2*5 + 8 + 9/9 + 3/3

Edit: 91=(8*2*5/8)*9 +9/3/3 (we also found another two combinations for 90)

petrw1 · 2019-01-12, 06:38

Quote:

Originally Posted by LaurV

you missed an 8 :fail:

In fact, the 2*5 combination is quite welcomed to make tens, hehe
90 = 8*2*5 + 8 + 9/9 + 3/3

Edit: 91=(8*2*5/8)*9 +9/3/3 (we also found another two combinations for 90)

My bad

henryzz · 2019-01-14, 11:48

92 = 8*2*5+8+((9+9/3)/3)
93 = 8*2*5+8-(9/9-3-3)

unconnected · 2019-01-14, 12:01

94=8*2*5+8-9+9+3+3
95=8*2*5+8+9/9+3+3
96=8*2*5-8+9+9+3+3

henryzz · 2019-01-14, 12:14

97=(8+2)*(5+8+9-9-3)-3
98=-8-2+(5+8)*9-9+3-3

unconnected · 2019-01-14, 13:14

99=8/2+5+8+9*9+3/3
100=8+2-5+8+9*9+3+3
101=8*2+5+8+9*9-3*3

While searching for 99, I've found several representations for 100:
100=8/2+5+8+9*9+3/3
100=8*2-5+8+9*9+3-3
100=8+2*5-8+9*9+3*3
100=8*2+5-8+9*9+3+3
Interesting, how many total of them exists?

henryzz · 2019-01-14, 13:43

Quote:

Originally Posted by unconnected

99=8/2+5+8+9*9+3/3
100=8+2-5+8+9*9+3+3
101=8*2+5+8+9*9-3*3

While searching for 99, I've found several representations for 100:
100=8/2+5+8+9*9+3/3
100=8*2-5+8+9*9+3-3
100=8+2*5-8+9*9+3*3
100=8*2+5-8+9*9+3+3
Interesting, how many total of them exists?

I also found one for 100:
100=(8+2)*(5+8-9+9/3+3)

102=8*(2+5+8)-9-9+3-3

2019-01-14, 12:14	#53
henryzz Just call me Henry "David" Sep 2007 Cambridge (GMT/BST) 2³×3×5×7² Posts	97=(8+2)(5+8+9-9-3)-3 98=-8-2+(5+8)9-9+3-3 Last fiddled with by henryzz on 2019-01-14 at 12:17

2019-01-14, 13:14	#54
unconnected May 2009 Russia, Moscow A1B₁₆ Posts	99=8/2+5+8+99+3/3 100=8+2-5+8+99+3+3 101=82+5+8+99-33 While searching for 99, I've found several representations for 100: 100=8/2+5+8+99+3/3 100=82-5+8+99+3-3 100=8+25-8+99+33 100=82+5-8+99+3+3 Interesting, how many total of them exists? Last fiddled with by unconnected on 2019-01-14 at 13:19*

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2019-01-12, 00:29	#46
Batalov "Serge" Mar 2008 Phi(4,2^7658614+1)/2 3⁶·13 Posts	Killjoy :-) I was lazily thinking about running the same-ish script and then I thought that people will say "Killjoy!" so I didn't.

2019-01-12, 03:16	#48
petrw1 1976 Toyota Corona years forever! "Wayne" Nov 2006 Saskatchewan, Canada 11104₈ Posts	90 = 8 * 2 * 5 + 9 + 9 / 3 / 3

2019-01-14, 11:48	#51
henryzz Just call me Henry "David" Sep 2007 Cambridge (GMT/BST) 2³·3·5·7² Posts	92 = 825+8+((9+9/3)/3) 93 = 825+8-(9/9-3-3)

2019-01-14, 12:01	#52
unconnected May 2009 Russia, Moscow 5033₈ Posts	94=825+8-9+9+3+3 95=825+8+9/9+3+3 96=825-8+9+9+3+3