crossnumber #8

[Till]

A challenging puzzle I found mentioned on https://blogs.ams.org/blogonmathblogs/ :

http://chalkdustmagazine.com/regular...mber-issue-08/

[science_man_88]

Originally Posted by Till

A challenging puzzle I found mentioned on https://blogs.ams.org/blogonmathblogs/ :

http://chalkdustmagazine.com/regular...mber-issue-08/

a few things.
9D,36A,20D,3D,4D,22D,8D,26D,23A,5D, and 6D have to all be 2 mod 5 and 6 mod 7 ( so 27 mod 35)
21A is 257
16D and 3A both show 18A<72, if different 18A<69
1A is surrounded by numbers that only have 2's and 3's as factors because n^2-1=(n-1)*(n+1)

[petrw1]

Originally Posted by science_man_88

a few things.
9D,36A,20D,3D,4D,22D,8D,26D,23A,5D, and 6D have to all be 2 mod 5 and 6 mod 7 ( so 27 mod 35)
21A is 257
16D and 3A both show 18A<72, if different 18A<69
1A is surrounded by numbers that only have 2's and 3's as factors because n^2-1=(n-1)*(n+1)

I found this one MUCH easier than one I did a few months ago....only took me a few hours off and on.

Now lets hope I submitted the right sum

2 hints:
34A; Proth Numbers
14D: Triperfect number