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#1 |
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Jul 2014
3×149 Posts |
Hi, I'm reading something about Quadratic Fields from Hardy's "An introduction to the theory of numbers".
I've come to an impasse. There's a sentence which I've outlined in black which I don't understand. It says "is plainly equivalent to" but I simply can't how the statement about the norm is equivalent to the version of the division algorithm (with the inequality of Norms) above. I'd really appreciate some help making sense of it if possible. https://www.mersenneforum.org/attach...1&d=1541016049 |
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#2 | |
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Sep 2002
Vienna, Austria
3×73 Posts |
Quote:
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#3 |
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Dec 2012
The Netherlands
110101001102 Posts |
Also remember that N(αβ)=N(α)N(β).
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#4 |
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Jul 2014
3×149 Posts |
Thanks to both of you.
I'm nearly ready to move on after a whole day going crazy. |
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#5 |
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Dec 2012
The Netherlands
2×23×37 Posts |
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#6 |
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6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
100110001110002 Posts |
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#7 |
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Jul 2014
6778 Posts |
Hi again,
I've been reading on a bit in the book and there's something else I don't get. If I could have another hint or a clear explanation I'd be really grateful. https://www.mersenneforum.org/attach...1&d=1541344310 I've outlined something with a black line. The (14.7.2) refers to the inequality with this number on the page from my first post. Firstly, I don't see why Secondly, I don't see why chosing these values for r and s leads to the simple inequality It'd be nice if someone could point the way for me. BTW, I don't know how to embed an image into a post. If someone could explain it'd make things better. Last fiddled with by wildrabbitt on 2018-11-04 at 15:25 |
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#8 |
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Jul 2014
3·149 Posts |
Sorry I've made a mistake. I was looking at 14.7.1 rather than 14.7.2 .Should be okay now.
Actually, I didn't make a mistake. My mistake was thinking I'd made one. Last fiddled with by wildrabbitt on 2018-11-04 at 17:03 |
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#9 | ||
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Dec 2012
The Netherlands
2×23×37 Posts |
Quote:
\[ |(r-x)^2-m(s-y)^2|<1.\] In particular, this must hold if we take \(r=s=\frac{1}{2}\). Putting \(\mu=-m>0\), there must exist integers x and y satisfying \[ \left(\frac{1}{2}-x\right)^2+\mu\left(\frac{1}{2}-y\right)^2<1.\] But for all integers x we have \((\frac{1}{2}-x)^2\geq\frac{1}{4}\) and similarly for y ... Quote:
But don't put too many full pages of Hardy & Wright on this public forum or we'll get intro copyright trouble!
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#10 |
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Jul 2014
3×149 Posts |
Thanks Nick.
I see now. That's very helpful. Is it possible for the pages to be deleted. I don't mind. |
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#11 |
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
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