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Old 2018-10-06, 03:41   #12
LaurV
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Hm... according with what the talk is talking here, I may have to waste my weekend playing with triangles... (didn't start yet, but it is really tempting!)
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Old 2018-10-06, 04:09   #13
axn
 
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Quote:
Originally Posted by bsquared View Post
(on the max-sized grid)
There is no "the" max-sized grid, right? If I'm not mistaken, these are the allowable grids (of points).
Code:
10x67
11x61
12x55
13x51
14x47
15x43
16x41
17x38
18x36
19x34
20x32
21x31
22x29
23x28
24x27
25x26
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Old 2018-10-06, 04:27   #14
a1call
 
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Quote:
Find a solution for N=11 and the L1*L2<=600.
Largest near square grid is a matrix of 25x24=600
Largest maximally elongated possible grid is a matrix of 6x100.

For 6 <= L1 <=100
L2 <= 600\L1


Last fiddled with by a1call on 2018-10-06 at 04:43
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Old 2018-10-06, 04:34   #15
axn
 
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Quote:
Originally Posted by a1call View Post
Largest near square grid is a matrix of 25x24=600
Largest maximally elongated possible grid is a matrix of 6x100.

For 6 <= L1 <=100
L2 = 600\L1

Right, that's the length of the grid. I'm talking about the points. n points x m points = (n-1) length x (m-1) length

Also, for placing N points successfully, you'll need at least (N-1) points x (N-1) points grid.
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Old 2018-10-06, 04:41   #16
a1call
 
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There are only 11 points placed on a grid with a maximum of 600 cells. Any 3 point subset of the 11 points forms a triangle. There are 165 different 3-combinations of 11 points, forming 165 triangles none of which may have the same area as any other.
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Old 2018-10-06, 05:53   #17
bsquared
 
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Quote:
Originally Posted by axn View Post
There is no "the" max-sized grid, right? If I'm not mistaken, these are the allowable grids (of points).
Code:
10x67
11x61
12x55
13x51
14x47
15x43
16x41
17x38
18x36
19x34
20x32
21x31
22x29
23x28
24x27
25x26
Yes, you're right. I used L1,L2 = 23,26, corresponding to your 24x27 grid of points. I haven't tried the more elongated ones yet, maybe I should.

Best solution so far is now at 163 on the dimension 23x26 grid.
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Old 2018-10-06, 08:15   #18
LaurV
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Scratch that! I am stupid! (I thought I solved it)

(advantages of being supermod, haha, can remove posts where my mouth was talking without me...)

Last fiddled with by LaurV on 2018-10-06 at 08:19
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Old 2018-10-07, 02:02   #19
Batalov
 
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It is a fun puzzle!
A solution for n points contains n (n-1)-point solutions in it.

Without the L1*L2<=600 constraint it is easy to find a sparse set, e.g.
[[26,11], [32,10], [0,24], [17,0], [34,6], [32,18], [2,14], [31,2], [7,3], [21,25], [10,25]]

Now, need to tighten the cage...
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Old 2018-10-07, 15:57   #20
Batalov
 
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Tightening the solution "from above".

I have a few S=700 solutions, S=663 and an S=644 solution...
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Old 2018-10-07, 19:30   #21
a1call
 
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Just not to have misdirected anyone, it's not clear to me if the grid size of L1xL2<=600 is based on the L's being counted from 0 or 1.
If the former then an actual grid cell number of 26x25=650 or less would be valid.
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Old 2018-10-07, 19:36   #22
Batalov
 
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Quote:
Originally Posted by a1call View Post
Just not to have misdirected anyone, it's not clear to me if the grid size of L1xL2<=600 is based on the L's being counted from 0 or 1.
If the former then an actual grid cell number of 26x25=650 or less would be valid.
It is perfectly clear when you follow the worked example for (note) 3x3 N=4 solution.
Because it uses dots with coordinates ranging from 0 to 3, you have your answer right there.

It is like a Go board: for which the grid has only 18x18 squares (in terms of this IBM problem, its area is 324), but you can use 19x19 positions to put a stone!
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