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#1 |
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Mar 2018
2·5·53 Posts |
https://solutionsti360.ca/MATH/pfgw/stats.html
At this link you can join in the ec-primes search. |
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#2 | |
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Just call me Henry
"David"
Sep 2007
Cambridge (GMT/BST)
16F816 Posts |
Quote:
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#3 |
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"Carlos Pinho"
Oct 2011
Milton Keynes, UK
3×17×97 Posts |
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#4 |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
947710 Posts |
Why is this project so slow?
Even one computer is enough to quickly find: (2^75894-1)*10^22847+2^75893-1 (2^79798-1)*10^24022+2^79797-1 (2^92020-1)*10^27701+2^92019-1 ... What's more - these are known to FactorDB for months (since March). ________________ Ah, there it is https://oeis.org/A301806 2, 3, 4, 7, 8, 12, 19, 22, 36, 46, 51, 67, 79, 215, 359, 394, 451, 1323, 2131, 3336, 3371, 6231, 19179, 39699, 51456, 56238, 69660, 75894, 79798, 92020, 174968, 176006, 181015, 285019, 331259 Last fiddled with by Batalov on 2018-07-25 at 07:03 |
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#5 | |
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Mar 2018
10000100102 Posts |
Quote:
yes I found that values, but I have yet not found a probable prime congruent to 6 (mod 7) |
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#6 |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
36·13 Posts |
So, these are not EC primes.
Rather they are PG primes, aren't they? |
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#7 |
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Mar 2018
2×5×53 Posts |
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#8 |
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Mar 2018
2×5×53 Posts |
pg(k) are numbers of the form =(2^k-1)*10^d+2^(k-1)-1 where d is the number of decimal digits of 2^(k-1)-1.
The k for wich pg(k) is prime are: 2, 3, 4, 7, 8, 12, 19, 22, 36, 46, 51, 67, 79, 215, 359, 394, 451, 1323, 2131, 3336, 3371, 6231, 19179, 39699, 51456, 56238, 69660, 75894, 79798, 92020, 174968, 176006, 181015, 285019, 331259, 360787, 366770 I call a(1)=2, a(2)=3 a(3)=4 a(4)=7...the terms of the sequence Now look at a(7s)'s a(7)=19 is prime a(14)=215 is a multiple of 215 a(21)=3371 is prime a(28)=75894 is -1 (mod 215) a(35)=331259 is prime They seem not random at all!!! |
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#9 |
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6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
230738 Posts |
I moved this to your blog area.
Keep your stuff there. You have been previously warned to not post your every thought elsewhere in the forum. If you don't behave, you can lose your posting privileges. ![]()
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#10 |
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Mar 2018
2×5×53 Posts |
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#11 |
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"Luke Richards"
Jan 2018
Birmingham, UK
25·32 Posts |
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