Generating from 16 to 35 digit number in row (+1)

[pepi37]

Hi!
What program I can use to generate such "big "numbers ?
Excel round numbers if has above 16 digits, so it is not solution.
And I dont need primes, I need all numbers.

Thanks for any reply
example

800000000000000000
800000000000000001
800000000000000002
800000000000000003
800000000000000004
etc etc

[science_man_88]

Originally Posted by pepi37

Hi!
What program I can use to generate such "big "numbers ?
Excel round numbers if has above 16 digits, so it is not solution.
And I dont need primes, I need all numbers.

Thanks for any reply
example

800000000000000000
800000000000000001
800000000000000002
800000000000000003
800000000000000004
etc etc

A for loop in pari gp ? You can also generate random numbers in a range using an until loop and random(n).

[pepi37]

Originally Posted by science_man_88

A for loop in pari gp ? You can also generate random numbers in a range using an until loop and random(n).

Please write example
Thanks

[Dubslow]

On the face of it, your question seems slightly insane. There isn't enough space on your hard drive to store 10^35 numbers.

[pepi37]

Originally Posted by Dubslow

On the face of it, your question seems slightly insane. There isn't enough space on your hard drive to store 10^35 numbers.

I need 2500 numbers , not all :-)

[science_man_88]

Originally Posted by pepi37

I need 2500 numbers , not all :-)

[1*10^15..1*10^15+2499] would have potential to work.

[kar_bon]

Using Excel:
- column A (text-formatted) with "80000000000" (or your length/number you need)
- column B (special format with leading zeros") with "0001" etc.

- save as "prn"

[S485122]

You can use Excel, but treat the numbers as strings,: concatenate the string "80000000000000" with the numbers from 0 to 2499 modified by a mask.
Put the numbers from 0 to 2499 in the A column and in the B1 cell ="80000000000000"&TEXT(A1;"0000"), then copy the formula down. (The 4 0's in the "0000" format string ensures you have the initial 0's and that all numbers have 4 digits.) Then it is an easy task to copy the result in a text file... (Unfortunately the name of function changes according to the language of the interface so if your Excel is in another language you will have to change the name of the function, f.i. in Spanish it is TEXTO() and in Italian TESTO().)

I just tested and it seems you can directly use the TEXT() function with the "800000000000000000" mask as in column C of the attached Excel spreadsheet.

Jacob

[Batalov]

ABC2 800000000000000000+$a
a: from 0 to 25

Replace 800000000000000000 with whatever you want.

[CRGreathouse]

It's not clear what you mean. I'll give some examples in PARI/GP and you can pick whichever you think seem helpful.

Loop from a 16-digit number to a 35-digit number, doing calculations along the way:

for(n=10^15, 10^35-1, if(Mod(2, n^2)^(n-1)==1, print(n)))
\\ this won't finish before the sun swallows the earth

Make a list of 2500 18-digit numbers:

v=[8*10^17..8*10^17+2499];

Make a list of random numbers with 16 to 25 digits:

v=vector(2500,i, [10^15,10^35-1]);

Loop through numbers from 10^15 to roughly 10^35 in equal-sized steps, doing a calculation along the way:

s=0; forstep(n=10^15,10^35, 40016006402561024409363745498199, s+=sqrt(n)); s

[pepi37]

Thanks to all, Excel mask works perfectly!