![]() |
|
|
#1 |
|
Nov 2004
24 Posts |
We all know fermat's theorem that states: if p is a prime and (p,a)=1 then p divides a^(p-1)-1. I noticed that p divides also: a^k(p-1)-1. Is this a well known characteristic?
Second question: what about the infinite sums -c, and in particularly when c=1 ? like 1-1+1-1+... Last question: does anybody know if new progresses were made in defining the necessary conditions for a function to be defined with a Fourier series? Greetings |
|
|
|
|
|
#2 | |
|
Jun 2003
The Texas Hill Country
32·112 Posts |
Quote:
a^(M*N)-1 = (a^M-1)*(a^(M*(N-1)) + a^(M*(N-2)) + ... + a^M + 1) |
|
|
|
|
|
|
#3 | |
|
Bronze Medalist
Jan 2004
Mumbai,India
22×33×19 Posts |
Quote:
![]() 2nd. Question: take the first term separately and group the next in twos We get the sum as (1) Any other grouping will give (0) Mally
|
|
|
|
|
|
|
#4 | |
|
∂2ω=0
Sep 2002
República de California
5·17·137 Posts |
Quote:
|
|
|
|
|
|
|
#5 |
|
Bronze Medalist
Jan 2004
Mumbai,India
22×33×19 Posts |
Crook
[Second question: what about the infinite sums -c, and in particularly when c=1 ? like 1-1+1-1+./UNQUOTE].. It will be interesting to see a different and surprising answer to the ones Ive given. The answer was given by Guido Grandi a priest and professor of Pisa known for his study of rosaces (r=sin(n*theta) and other curves which resemble flowers. In the 18th century, also known for its mysticism, Guido considered the formula1/2 = 1-1+1-1 ... = 0+0+0.. as the symbol for Creation from Nothing. He obtained the result 1/2 by considering the case of a father who bequeaths a gem to his two sons who each may keep the bauble for one year in alternation. It then belongs to each son for one half! Source: 'A concise history of mathematics' by Dirk J. Struick Mally
|
|
|
|
|
|
#6 |
|
Bronze Medalist
Jan 2004
Mumbai,India
22·33·19 Posts |
Thank you Crook for investigating the mystery of the infinite series. As a result I have been able to go further in this investigation. However I must restrict this post by giving just one more rendition. In the 19th century Bernard Bolzano was the first to treat this problem on a sound and logical manner. Since Zeno's paradoxes had put mathem'cians in a flummux there was a lot of speculation as to how to relate to infinity. Then Bolzano came along and treated the problem on a war footing. Consider the series S = a -a + a -a +a -a +.............. If we group the terms thus we get S = (a-a) +(a-a) ......... = 0 On the other hand we group the terms in a 2nd. way We can write S =a -(a-a) -(a-a) -(a-a)......... a-0-0-0 =a Again by still another grouping S =a -(a-a+a-a +a-a............. S =a- S Hence 2S=a or S=a/2 (so the learned proffessor/priest of Pisa Guido Grandi mentioned in an earlier post was not so wrong after all) Today with maths on a firmer footing we can label it as a class of oscillating series between the values of 0 and a Even more startling are the results obtained from the series in the special case when a = 1 I will reserve this for another post. For further reading; 'Riddles in maths' by Eugene Northrop 1960 'The Paradoxes of the Infinite' by Bernard Bolzano1851 . Mally
Last fiddled with by mfgoode on 2005-05-05 at 17:26 Reason: typo error |
|
|
|
![]() |
| Thread Tools | |
Similar Threads
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Modified Fermat's theorem | devarajkandadai | Number Theory Discussion Group | 2 | 2017-06-23 04:39 |
| Modified fermat's last theorem | Citrix | Math | 24 | 2007-05-17 21:08 |
| Fermat last theorem generalization | Damian | Math | 5 | 2007-02-06 00:43 |
| Fermat's Theorem-tip of the iceberg? | devarajkandadai | Miscellaneous Math | 2 | 2006-06-16 08:50 |
| Fermat,s Theorem | devarajkandadai | Miscellaneous Math | 3 | 2004-06-05 10:15 |