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#1 |
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Sep 2011
3×19 Posts |
The probability that a random number below X is B-smooth is given by u-u, where u=ln(X)/ln(B). However, I would like the do the inverse, that is, given the smoothness probability and B, how do I solve for X?
I have a solution via Newton method. Is there a closed form? |
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#2 | |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
36·13 Posts |
Quote:
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#3 | |
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Sep 2011
3×19 Posts |
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#4 | |
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Basketry That Evening!
"Bunslow the Bold"
Jun 2011
40<A<43 -89<O<-88
3×29×83 Posts |
Quote:
The links he provides are sources for p ≈ some_better_function_of(X, B). Find those better functions before trying to invert them. |
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#5 | |
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Sep 2011
3·19 Posts |
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#6 | |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
36×13 Posts |
Incidentally, I have just heard from much more knowledgeable people, and I will simply quote:
Quote:
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#7 |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
36·13 Posts |
And for the Inverse of Smoothness Probability question, you want a reasonable numerical estimate the inverse of Dickman function.
So you want to take Newton method on the inverse of Dickman ρ - because if you know the derivative of Dickman ρ by definition, then you know the derivative of the inverse of Dickman ρ. |
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